From the description we can infer that we have the expression:
![41^{- \frac{2}{5} }](https://tex.z-dn.net/?f=41%5E%7B-%20%5Cfrac%7B2%7D%7B5%7D%20%7D)
.
Now, to write our expression as a as a root, we are going to apply the law of exponents:
![x^{-n}= \frac{1}{x^n}](https://tex.z-dn.net/?f=x%5E%7B-n%7D%3D%20%5Cfrac%7B1%7D%7Bx%5En%7D%20)
first
![41^{- \frac{2}{5} }= \frac{1}{41^{ \frac{2}{5} }}](https://tex.z-dn.net/?f=41%5E%7B-%20%5Cfrac%7B2%7D%7B5%7D%20%7D%3D%20%5Cfrac%7B1%7D%7B41%5E%7B%20%5Cfrac%7B2%7D%7B5%7D%20%7D%7D%20)
Next, we are going to apply the law about fractional exponents:
![x^{ \frac{m}{n}}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
![\frac{1}{41^{ \frac{2}{5} }}= \frac{1}{ \sqrt[5]{41^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B41%5E%7B%20%5Cfrac%7B2%7D%7B5%7D%20%7D%7D%3D%20%5Cfrac%7B1%7D%7B%20%5Csqrt%5B5%5D%7B41%5E2%7D%20%7D%20)
We can conclude that the
value of B is 2.
X equals negative 2. It says i need to write at least 20 characters so ignore this part, its nonsense :)
To find the gradient of a line we first hv to find the formula
so Gradient=√X1-x2and √y1-y2
((-2,1) and (0,-5)) line 1
line 2(0,-1) and (1,0)
first we will work for line 1
X1 is -2
X2 is -0
Y1 is 1
Y2 is -1
so y=x-1
so we substitute the values
1--1=-2--0
so,
1+1=-2+0
2=-2
-0
So the equation 1 line 1 is not true
we will now go to equation 2 line 2
the equation is 3x+y=-5
we substitute the values
3(-2--0)+1--1=-5
3(-2)+-2=-5
-6+-2=-5
-8= -5
group like terms
Ur answer should look like this -3
So the answer is 3x+y=-5
There are so many types of angles, let's see what we've got here!
--(5x - 17) and 48 are alternate interior angles, which means that they are congruent.
--(5x - 17) and y are supplementary angles.
--48 and y are same-side interior angles, which means that they are also supplementary.
Let's solve for x first.
5x - 17 = 48
5x = 65
x = 13
Now, let's solve for y.
48 + y = 180
y = 132
Hope this helps!! :)