Consider the line y=9x-8

Mathematics

1 answer:

jasenka [17]3 years ago

7 0

Answer:

y=9x+75

Step-by-step explanation:

since we know that the slope must be the same for two lines to be proportional, we are gonna start there.

so our equation is: y= 9x + b

we need to find b to complete our equation, so substitute in the points we were given.

3 = 9(-8) + b

so now,

3 = -72 + b

now we have to isolate b to find out what it is,

3 = -72 + b

+72 +72

so now: 75= b

Put that back into the starting equation: y = 9x + 75

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How does the graph of y=-3√2x-4 compare to the graph of y=-3√x-4?

kifflom [539]

Assuming the graph is y=-3(√2x)-4 and y=-3√(x-4) the transformation would be:

The graph is compressed horizontally by a factor of 2
x=1/2x'
y=-3(√2x)-4
y=-3(√x')-4 

moved left 4
x=x'-4
y=-3(√x)-4
y=-3(√x'-4)-4

moved down 4
y=y'-4
y=-3(√x-4)-4
y'-4=-3(√x'-4)-4
y'=-3(√x'-4)-4 +4
y'=-3(√x'-4)

Answer: C. The graph is compressed horizontally by a factor of 2, moved left 4, and moved down 4.

6 0

3 years ago

Read 2 more answers

Given: ∆ABC, AC = 12, AB = BC = 10 Find: m∠A, m∠C, m∠B

4vir4ik [10]

Answer:

m∠A ≈ 53.13°
m∠B ≈ 73.74°
m∠C ≈ 53.13°

Step-by-step explanation:

An altitude to AC bisects it and creates two congruent right triangles. This lets you find ∠A = ∠C = arccos(6/10) ≈ 53.13°.

Since the sum of angles of a triangle is 180°, ∠B is the supplement of twice this angle, so is about 73.74°.

m∠A = m∠C ≈ 53.13°

m∠B ≈ 73.74°

_____

The mnemonic SOH CAH TOA reminds you of the relation between the adjacent side, hypotenuse, and trig function of an angle:

Cos = Adjacent/Hypotenuse

If the altitude from B bisects AC at X, triangle AXB is a right triangle with side AX adjacent to the angle A, and side AB as the hypotenuse. AX is half of AC, so has length 12/2 = 6, telling you the cosine of angle A is AX/AB = 6/10.

A diagram does not have to be sophisticated to be useful.