Which equation is y = –6x^2 + 3x + 2 rewritten in vertex form? plz help will give
1 answer:
Y = –6.x²<span> + 3.x + 2.
Its vertex form is (y-k) = a(x-h)</span>², where the vertex is V(h , k).
Let's calculate k and h from the original function y = - 6.x² + 3.x + 2.
a) the maximum is when f(0) = k→ -6(0)² + 3(0) + 2 , hence k = 2
b) The axis of symmetry is equal to x = -b/2.a:
x= -(3)/2.(-6) → x = 1/4 (1/4 is = h); Now replace k & h in the Vertex form
y-k = a(x-h)²
y- 2 = -6(x-1/4)²
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13 and 53
Step-by-step explanation:
First Integer: x
Larger integer: 5x-12
66=x+(5x-12)
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Check Work:
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Answer:
see explanation
Step-by-step explanation:
10^3x=98
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