Question

Using substitution x+3y=3 3y-2x=12

Answer 1

Answer:

x = -3

y = 2

Step-by-step explanation:

Ok this is a long one but bear with me lol, i promise i will make it easy to understand, performing one step at a time.

So we are given 2 equations right? We can take any of these one equation and isolate any one variable, either x or y, I will take the first equation and isolate x from it cuz it's the easiest way;

=> x + 3y = 3

=> x = -3y + 3 (Let's pretend this is not an equation for x but a "value")

Now that we have the x isolated from first equation, we can substitute x "value" in for the x in second equation. To solve for y;

=> 3y - 2 (-3y + 3) = 12

=> 3y + 6y - 6 = 12

=> 9y - 6 = 12

=> 9y = 12 + 6

=> 9y = 18

=> y = 18/9

=> y = 2

At this point we are almost done with the question! So since we got a real value for one of our variable (which in this case is y-value), we can substitute that in any of the given equation, We can also use the equation where in we isolated "x", so I'll use that cuz it's gonna require less steps, to find the real x-value:

=> The equation we found out up there is: x = -3y + 3

=> Now just simply substitute the y-value we figured in the equation above:

=> x = -3y + 3

=> x = -3(2) + 3

=> x = -6 + 3

=> x = -3

Ayee we did it lol so the final answer would be:

x = -3

y = 2

I really hope this made sense, and that it helps!

Answer 2

Step-by-step explanation:

Given :-

• x + 3y = 3
• 3y - 2x = 12

And we need to solve the equation using Substituting method . So on taking the first equation ,

$\rm\implies x + 3y = 3 \\\\\rm\implies x = 3 - 3y$

Put this value in (ii) :-

$\rm\implies 3y - 2x = 12 \\\\\rm\implies 3y - 2(3-3y)=12\\\\\rm\implies 3y -6-6y = 12 \\\\\rm\implies -3y = 18 \\\\\rm\implies y = -6$

Put this Value in (I) :-

$\\\\\rm\implies x = 3-3*-6 \\\\\rm\implies x = 3+18 \\\\\rm\implies x = 21$

Hence the Value of x is 21 and y is (-6) .