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IgorLugansk [536]
2 years ago
5

100 100 Students, drow anywhere on this slide!

Mathematics
1 answer:
Brut [27]2 years ago
3 0

Answer:

Im sorry what?

Step-by-step explanation:

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6 yd<br> 4 yd<br> 7 yd<br> 4 yd<br> Perimeter:<br> Area:<br> Help me find the area and the permiter
morpeh [17]

Step-by-step explanation:

Assuming figure to be trapezoid,

Perimeter=6+4+7+4yd

=21 yd

Area of trapezoid=((6+7)/2) x ((4)^2-(0.5)^2)

=(13/2)x(16-0.25)

=6.5 x 15.75

=102.375 Sq yards

8 0
2 years ago
Find f(-2) if f(x) = x + x + 7. f(-2) =
Lynna [10]

Answer:

f(-2) = 9

Step-by-step explanation:

Given that,

f(x) = x² + x + 7

We need to find the value of f(-2).

Put x = -2 in the given function.

f(-2) = (-2)² + (-2) + 7

= 4-2+7

= 9

Hence, the value of f(-2) is equal to 9.

3 0
3 years ago
PLEASE HELP! WILL MARK BRAINLIEST!
Kaylis [27]

Answer:

320 meters

Step-by-step explanation:

x² + 200x = 166400

It's a square, area should be side²

x² + 2(x)(100) = 166400

x² + 2(x)(100) + 100² = 166400 + 100²

(x + 100)² = 176400

x + 100 = 420

Since these are sides, we just consider the positive square root

x + 100 = 420

x = 320m

7 0
3 years ago
{0.2x+0.6y=3.6 0.4x-0.9y=-1.2} what is the answer
MariettaO [177]

Answer:

68266==874624./4

Step-by-step explanation:

77353877473=287365-2874662kkh=2875

4 0
1 year ago
????⃗ (x,y)=(3x−4y)????⃗ +2x????⃗ F→(x,y)=(3x−4y)i→+2xj→ and ????C is the counter-clockwise oriented sector of a circle centered
Karolina [17]

By Green's theorem, the integral of \vec F along C is

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(2x)}{\partial x}-\frac{\partial(3x-4y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=6\iint_D\mathrm dx\,\mathrm dy

which is 6 times the area of D, the region with C as its boundary.

We can compute the integral by converting to polar coordinates, or simply recalling the formula for a circular sector from geometry: Given a sector with central angle \theta and radius r, the area A of the sector is proportional to the circle's overall area according to

\dfrac A{\frac\pi3\,\rm rad}=\dfrac{16\pi}{2\pi\,\rm rad}\implies A=\dfrac{8\pi}3

so that the value of the integral is

\dfrac{6\times8\pi}3=\boxed{16\pi}

6 0
3 years ago
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