Ask question

Ask question

All categories

3 years ago

6

Hey I need some help!! Does anyone mind giving me the answers and explain how? I really don’t understand. PS the question is in

the pic, I will mark u brainlist if you help!! Have a wonderful day everyone!!!!! Technically I’m supposed to match them btw!

1 answer:

Ksenya-84 [330]3 years ago

6 0

Answer:

2x2x2x5

Step-by-step explanation:

2x2x2x5 equals 40

You might be interested in

Help me prove this trig identity

alexdok [17]

Hello here is a solution:

3 0

3 years ago

Did anyone take the Linear Functions Unit Test for CCA grade 10?? I could really use the help!!

gulaghasi [49]

Yeah post the questions I'll see if I can answer them

6 0

3 years ago

PLEASE ANSWER QUICKLY AND HELP ME!! THANK YOU SO MUCH!!

coldgirl [10]

Hello there!

To start off this problem, let's replace f(x) with x in the equation. This gives us the following.

$x= \dfrac{3}{4} x+12$

Subtract 3/4*x from both sides.

$x- \dfrac{3}{4} x=12$

$\dfrac{4}{4} x-\dfrac{3}{4}x=12$

$\dfrac{1}{4} x=12$

Now, multiply both sides by 4 to eliminate the fraction on the left side.

$x=12*4=48$

Your answer is B. Hope this helps! :)

5 0

3 years ago

Three ladders measure 5 3/4 meters, and 7 1/4 meters in length. What is the difference between the longest and shortest lengths?

Dovator [93]

7 1/4 - 5 3/4= 1 1/2 because you can either 1) change it into decimals: 7.25-5.75 and do simple subtraction or... 2) u can change the 7 to a 6 and add 4 to the numerator of 1/4 making the equation 6 5/4 - 5 3/4 = 1 2/4 which simplified to 1 1/2 I hope I didn’t confuse you! :))

3 0

3 years ago

The coordinates G(7,3), H(9, 0), (5, -1) form what type of polygon?

Marrrta [24]

Answer:

Is an acute triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

G(7,3), H(9, 0), I(5, -1)

step 1

Find the distance GH

substitute in the formula

$d=\sqrt{(0-3)^{2}+(9-7)^{2}}$

$d=\sqrt{(-3)^{2}+(2)^{2}}$

$GH=\sqrt{13}\ units$

step 2

Find the distance IH

substitute in the formula

$d=\sqrt{(0+1)^{2}+(9-5)^{2}}$

$d=\sqrt{(1)^{2}+(4)^{2}}$

$IH=\sqrt{17}\ units$

step 3

Find the distance GI

substitute in the formula

$d=\sqrt{(-1-3)^{2}+(5-7)^{2}}$

$d=\sqrt{(-4)^{2}+(-2)^{2}}$

$GI=\sqrt{20}\ units$

step 4

Verify what type of triangle is the polygon

we know that

If applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$ ----> is a right triangle

$c^{2}> a^{2}+b^{2}$ ----> is an obtuse triangle

$c^{2}< a^{2}+b^{2}$ ----> is an acute triangle

where

c is the greater side

we have

$c=\sqrt{20}\ units$

$a=\sqrt{17}\ units$

$b=\sqrt{13}\ units$

substitute

$c^{2}= (\sqrt{20})^{2}=20$

$a^{2}+b^{2}=(\sqrt{17})^{2}+(\sqrt{13})^{2}=30$

therefore

$c^{2}< a^{2}+b^{2}$

Is an acute triangle

6 0

3 years ago

Read 2 more answers