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Tcecarenko [31]
3 years ago
6

Evaluate the expression 2x^2-y^1+3x^0 for x =3 and y=5

Mathematics
2 answers:
andreev551 [17]3 years ago
8 0

Answer:

Evaluate the expression 2x^2-y^1+3x^0 for x =3 and y=5

GarryVolchara [31]3 years ago
8 0
I think it’s 14 I’m not sure
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3 years ago
Teresa earned scores of 88, 84, 88 points and 91 points on 4 test what is the lowest score she can get on the fifth test and sti
Usimov [2.4K]

Answer:

99 points

Step-by-step explanation:

Average of a data a is the sum of the data divided by the number of data.

Average = sum of data ÷ number of data

A = T/n .....1

For the average of 5 test to be 90.

The total sum of score must be;

Number of tests n = 5

Average A = 90

Substituting into equation 1

90 = T/5

T = 90×5 = 450 points

The total score must be equal to 450 point to have an average of 90 points

The sum of the first four test is;

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Let x represent the first score,

351 + x = 450

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5 0
3 years ago
It’s asking for the area<br> Please help! Thank you!
Eddi Din [679]

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Step-by-step explanation:

To find the area you multiply the sides so it should be (x+4)(x+5) which is x^2+9x+20. Good luck!

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