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vichka [17]
3 years ago
9

Find the distance between R(-2,2) and S(4,1)

Mathematics
1 answer:
Fiesta28 [93]3 years ago
5 0

the square root of 37 is the answer

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The Loft Theater has a center seating section with 3c + 8 rows and 4c-1 seats in each row. Write an expression for the total num
yulyashka [42]

If there are n rows

And if each row has m seats.

Then the total number of seats shall be n × m.

Here

Number of rows = (c+8)

And number of seats in each row = (4c-1)

Using the concept

Total number of seats

= (c+8)(4c-1)

FOILing or Distributing we get

= c(4c) + c (-1) + 8(4c) +8 (-1)

= 4c² - c + 32 c -8

Combining like terms

=4c² +31c - 8

The expression for total number of seats = 4c² + 31c -8

4 0
3 years ago
Excuse me can you help it’s proportional relationship
kirza4 [7]
Sorry, I’m busy but I’ll help you with this one.

$18.50 x 30 = $555

100% - 15% = 85%

$555 / 100 = $5.55

$5.55 x 85 = $471.75

Lab Coats will cost $471.75
8 0
3 years ago
Your sister goes to a restaurant with her friends. The total for the food is $50.43. How much TAX will you pay if the percentage
torisob [31]

Answer:

3.0258

Step-by-step explanation:

50.43*6%=3.0258

6 0
3 years ago
Find the product of 3(-1/6) (-2/5)
Allisa [31]

Answer:

= 1/5 ( 0.2 in decimal )

Step-by-step explanation:

3(-1/6) (-2/5)

= 1/5 ( 0.2 in decimal )

3 0
3 years ago
Zeller industries bought a computer for $4600. It is expected to depreciate at a steady rate of 20% a year. When will the value
valentinak56 [21]

Answer:

About 3.73 yrs

Step-by-step explanation:

This is a compound decay problem. Which has the formula:

F=P(1-r)^t

Where

F is the future amount (we want it to be 2000)

P is the present amount (which is 4600)

r is the rate of decay, depreciation (20% per year means 20/100 = 0.2)

t is the time in years (which we want to find)

Substituting, we find:

F=P(1-r)^t\\2000=4600(1-0.2)^t\\2000=4600(0.8)^t\\0.4348=0.8^t

Now we take natural log (Ln) of both sides and solve:

Ln(0.4348)=Ln(0.8^t)\\Ln(0.4348)=tLn(0.8)\\t=\frac{Ln(0.4348)}{Ln(0.8)}\\t=3.73

So, it will take about 3.73 years for the value to depreciate to $2000

3 0
4 years ago
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