If there are n rows
And if each row has m seats.
Then the total number of seats shall be n × m.
Here
Number of rows = (c+8)
And number of seats in each row = (4c-1)
Using the concept
Total number of seats
= (c+8)(4c-1)
FOILing or Distributing we get
= c(4c) + c (-1) + 8(4c) +8 (-1)
= 4c² - c + 32 c -8
Combining like terms
=4c² +31c - 8
The expression for total number of seats = 4c² + 31c -8
Sorry, I’m busy but I’ll help you with this one.
$18.50 x 30 = $555
100% - 15% = 85%
$555 / 100 = $5.55
$5.55 x 85 = $471.75
Lab Coats will cost $471.75
Answer:
3.0258
Step-by-step explanation:
50.43*6%=3.0258
Answer:
= 1/5 ( 0.2 in decimal )
Step-by-step explanation:
3(-1/6) (-2/5)
= 1/5 ( 0.2 in decimal )
Answer:
About 3.73 yrs
Step-by-step explanation:
This is a compound decay problem. Which has the formula:
Where
F is the future amount (we want it to be 2000)
P is the present amount (which is 4600)
r is the rate of decay, depreciation (20% per year means 20/100 = 0.2)
t is the time in years (which we want to find)
Substituting, we find:
Now we take natural log (Ln) of both sides and solve:
So, it will take about 3.73 years for the value to depreciate to $2000
