Solve for x Need help on this
1 answer:
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Answer:
Hence, the perimeter of the triangles are:
P=123.2727 dm
P'=102.7272 dm
Step-by-step explanation:
In two similar triangles:
The ratio of the areas of two triangle is equal to the square of their perimeters.
Let A and A' represents the area of two triangles and P and P' represents their perimeter.
Then they are related as:
We are given:
A=72 dm^2 , A'=50 dm^2
and P+P'=226 dm.-----------(1)
i.e.
on taking square root on both the side we get:
Now putting the value of P in equation (1) we obtain:
Hence,
P=226-102.7272=123.2727
Hence, the perimeter of the triangles are:
P=123.2727 dm
P'=102.7272 dm
Answer:
Step-by-step explanation:
Begin by isolating x. To do this, you can substract 24 on both sides.
That's your answer. Any value of ''x'' must be greater than 28 for this inequality to be true.