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oksian1 [2.3K]
3 years ago
10

Pump a can empty a pool in 20 hours and pump b can empty it in 24 hours. working together, how long

Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0
I would guess 4 hours in that case
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Iodine-131 has a half-life of 8 days. How much would be left of an original 40 g sample after 40 days?
Yuri [45]

Answer:

d) 1.25 g

Step-by-step explanation:

If it has a half life of 40 days, there will be 5 half-lives in that span of time so if you divide 40 by 2, 5 times or just \frac{40}{2^{5} }, it will equal 1.25.

\frac{40}{2}=20\\

\frac{20}{2} =10

\frac{10}{2} =5

\frac{5}{2} =2.5\\

\frac{2.5}{2} =1.25

8 0
3 years ago
7/9 - 2/8 times 4/9 sum in simplest form
Nady [450]

7/9 -2/8 * 4/9 =

7/9 -1/4*4/9 =

7/9 -1/9 = 8/9

Answer: 8/9

7 0
3 years ago
What is the value of b?
Gnoma [55]

Answer:

the B value is The Middle number, which is the number next to and multiplied by the x

3 0
3 years ago
Mrs.Brooks lacks 7 from being fice times as old as her son. Six years from now she will lack 3 years from being three times as o
nalin [4]

Answer:

Step-by-step explanation:

Let the age of of Mrs brook be x

Age of her son be y

If Mrs.Brooks lacks 7 years from being five times as old as her son, this means;

x = 5y - 7 ..... 1

six years from now;

Mrs brooks age = x + 6

sons age = y + 6

If Six years from now she will lack 3 years from being three times as old as her son, this means;

x+ 6 = 3(y+6) - 3

x+6 = 3y + 18 - 3

x+6 = 3y + 15 .... 2

substitute 1 into 2;

(5y - 7)+6 = 3y + 15

5y - 1 = 3y + 15

5y-3y = 15 + 1

2y = 16

y = 8

substitute y = 8 into equation 1;

x = 5y - 7

x = 5(8)-7

x = 40-7

x = 33

Hence the mrs brook is 33 years old

her son is 8 years old

3 0
3 years ago
701 k- 523 km 445 m=
gregori [183]
1 \ km =1\ 000\ m\\\\701 \ km- 523 \ km \ 445 \ m = 700\ km\ 1\ 000\ m -523 \ km \ 445 \ m=177\ km\ 555\ m


7 0
3 years ago
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