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2 years ago

Please help me solve this whole problem!

Mathematics

1 answer:

kondor19780726 [428]2 years ago

3 0

Answer:

(0, -4)

rise/run = (-5/1)

x y

1 -9

2 -14

3 -19

4 -24

5 -29

6 -34

Step-by-step explanation:

You're going to have to graph it yourself.

Take the coordinated and just plot the points, then draw the line.

(1,-9)

(2,-14)

(3,-19)

(4,-24)

(5,-29)

(6,-34)

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The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe

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The height of container is 8 feet

Solution:

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

The volume of container is given as:

$v = length \times width \times height$

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Substitute eqn 1 and eqn 2 in above formula

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If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

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Also,

$h^2+4h+27 = 0$

Solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}$

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h = 8

$h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i$

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

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3 years ago

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Step-by-step explanation:

Problem One (left panel)

Question A

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