There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "
According to Pythagoras theorem,
note :
- p = perpendicular / opposite side
- b = base / adjacent side
- h = hypotenuse
let's solve for " y² " first ( square of other missing side )
now let's solve for " x " , by using pythagorous theorem
Approximate :
Looks more like Trig than Algebra II
They want us to apply the sum angle formula to 
5π/6 is 150°; I find it easier to think in degrees.
When the tangent of x is 3/4 that's a right triangle with opposite 3, adjacent 4 so hypotenuse 5. So a sine of 3/5 and a cosine of 4/5, both positive because we're told x is in the first quadrant.
The sine sum angle formula is
We know sin 150° = sin 30° = 1/2 and cos 150° = - cos 30° = -√3/2
Third choice
Answer:
74
Step-by-step explanation:
Using PEMDAS we can see that we need to do the parentheses first.
After that we need to add the answers together.
This gives us our answer of 74.
X=number of games played
just do simple multiplication
remember that orded pairs are (x,y)
x=5
y=0.50(5)+3
y=2.5+3
y=5.5
orderd pair is (5,5.5)
x=10
y=0.50(10)+3
y=5+3
y=8
ordered pair is (10,8)
x=20
y=0.50(20)+3
y=10+3
y=13
ordered pair is (20,13)
(5,5.5)
(10,8)
(20,13)
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