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LenKa [72]
3 years ago
12

Algebra 2: PLEASE HELP ME!!

Mathematics
1 answer:
vfiekz [6]3 years ago
3 0

Looks more like Trig than Algebra II

They want us to apply the sum angle formula to \sin(x + \frac{5 \pi}{6})

5π/6 is 150°; I find it easier to think in degrees.

When the tangent of x is 3/4 that's a right triangle with opposite 3, adjacent 4 so hypotenuse 5. So a sine of 3/5 and a cosine of 4/5, both positive because we're told x is in the first quadrant.

The sine sum angle formula is

\sin(a+b) = \sin a \cos b + \cos a \sin b

\sin(x+\frac{5\pi}{6}) = \sin x  \cos \frac{5\pi}{6} + \cos x \sin \frac{5\pi}{6}

We know sin 150° = sin 30° = 1/2 and cos 150° = - cos 30° = -√3/2

\sin(x+\frac{5\pi}{6}) = \frac 3 5  (- \sqrt{3}/2)  + \frac 4 5 (1/2)

\sin(x+\frac{5\pi}{6}) = \dfrac{ 4- 3\sqrt{3}}{10}

Third choice

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