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3 years ago

How did things change for Christians in 313 CE?

Mathematics

2 answers:

Viefleur [7K]3 years ago

6 0

Answer:

In 313 an edict of toleration for all religions was issued, and from about 320 Christianity was favoured by the Roman state rather than persecuted by it. But the empire was dying. The last of Constantine's line, Theodosius I (379–395), was the last emperor to rule over a unified Roman Empire.

Step-by-step explanation:

frosja888 [35]3 years ago

5 0

Answer:

In 313 CE, the emperor Constantine issued the Edict of Milan, which granted Christianity—as well as most other religions—legal status. ... Most other Christian sects were deemed heretical, lost their legal status, and had their properties confiscated by the Roman state.

Step-by-step explanation:

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Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$

And so the equation is

$x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0$

In order to have integer coefficients, you can multiply both sides of the equation by 8:

$8x^2 - 10 + 3 = 0$

5 0

3 years ago

WILL MARK BRAINIEST, QUESTION IS HARD, Ann works for a city’s parks and recreation department. She is looking for some commercia

MrRa [10]

Answer:

$x =320$

Step-by-step explanation:

Given

$x^2 + 200x = 166400$

Required

Find x

We have:

$x^2 + 200x = 166400$

Rewrite as:

$x^2 + 200x - 166400 = 0$

Expand

$x^2 + 520x - 320x - 166400 = 0$

Factorize

$x(x + 520) - 320(x + 520)= 0$

Factor out x + 520

$(x - 320) (x + 520)= 0$

Split

$x - 320 = 0\ or\ x + 520= 0$

Solve

$x = 320\ or\ x =- 520$

Side length must be positive;

So:

$x = 320$

4 0

3 years ago

Find the value of x. The diagram is not to scale.

DiKsa [7]

Sum of interior angles in a pentagon=540°

148+112+2x+2x+10+90=540

360+4x=540

4x=540-360

4x=180

x=180/4

x=45°

5 0

3 years ago

Hometown Grocery, Inc. has 50 comma 000 shares of common stock outstanding and 4 comma 000 shares of preferred stock outstandin

Anit [1.1K]

Answer:

$0.36 per share

Step-by-step explanation:

The data provided in the question are as follows

Common stock outstanding = 50,000 shares

Preferred stock outstanding = 4,000 shares

Par value of common stock = $4

Interest rate and par value of preferred stock = 9% and $100

Total dividend payment declared = $54,000

So, the amount of dividend for each share of common stock is

= (Total dividend payment declared - Preferred stock outstanding × interest rate × par value) ÷ (common stock outstanding)

= ($54,000 - 4,000 × $100 × 9%) ÷ (50,000 shares)

= ($54,000 - $36,000) ÷ (50,000 shares)

= $18,000 ÷ 50,000 shares

= $0.36 per share

7 0

3 years ago

Find the constant $a$ such that\[(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28.\]

Colt1911 [192]

The value of constant a is -5

Further explanation:

We will use the comparison of co-efficient method for finding the value of a

So,

Given

$(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\$

As it is given that

(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28

In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x

Comparing coefficient of x^3

$a-6 = -11\\a = -11+6\\a = -5$

So the value of constant a is -5

Keywords: Polynomials, factorization

Learn more about factorization at:

#LearnwithBrainly

4 0

3 years ago