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Irina-Kira [14]
3 years ago
7

How do I solve this problem to find ACD

Mathematics
2 answers:
UkoKoshka [18]3 years ago
3 0
A triangle equals 180 so you do....

90+45+x=180
135+x=180
-135 -135
x= 45

angle C is 45 degrees

then theres a linear equation for angle C, so you do...

45+x=180
-45 -45

x= 135

angle ACD= 135 degrees
olga_2 [115]3 years ago
3 0

Answer:

x=135

Step-by-step explanation:

135 !!!!!lollllll

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I have to take my geometry eoc im so nervous​
valentinak56 [21]
Good luck I really hope you past it then
6 0
3 years ago
Shawn incorrectly graphed the inequality -x-2y≥8 as shown below Explain shawn mistake ​rotate phone if u need to
Aleks04 [339]

Answer:

He failed to flip the inequality

y ≤-1/2x-4

Step-by-step explanation:

-x-2y ≥8

Add x to each side

-x+x-2y ≥x+8

-2y ≥x+8

Divide by -2.  Remember to flip the inequality

-2y/-2 ≤-1/2 x +8/-2

y ≤-1/2x-4

Shawn shaded the wrong side of the line.

Y is less than or equal to .  He failed to flip the inequality

3 0
3 years ago
Akash's cell phone bill was \$79.99$79.99dollar sign, 79, point, 99 per month for 333 months. His payments came out of his check
slega [8]

Answer:

A.

Step-by-step explanation:

The total amount Akash paid in those 3 months for his cell phone bill.

5 0
3 years ago
Read 2 more answers
Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.
Mama L [17]

Multiplying both sides by y^2 gives

xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1

so that substituting v=y^3 and hence \frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx} gives the linear ODE,

\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1

Now multiply both sides by 3x^2 to get

x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2

so that the left side condenses into the derivative of a product.

\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2

Integrate both sides, then solve for v, then for y:

x^3v=\displaystyle\int3x^2\,\mathrm dx

x^3v=x^3+C

v=1+\dfrac C{x^3}

y^3=1+\dfrac C{x^3}

\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}

6 0
3 years ago
A leatherback sea turtles was swimming at 850 below sea level. He went 165 meters and then descendes 165 meters. Draw a number l
Step2247 [10]

Answer:

The answer is below

Step-by-step explanation:

a) Let negative means the turtle position when descending and positive for going up. Therefore since the turtle was 850 meters below see level, it was at -850. It then moves 165 meters up, hence its new position is -685 meters (-850 + 165). Lastly it moves down 165 meters, hence its new position is -850 meters (-685 - 165)

b) The change in position is the sum of the movements = +165 - 165 = 0 meters.

5 0
3 years ago
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