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ikadub [295]
3 years ago
15

Help pleaseeeeeeeeee

Mathematics
1 answer:
Anna11 [10]3 years ago
8 0

where is the question sir??

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Kate wants to buy a bike that costs $250. She has $40 saved. She will also do 5 days of yard work earning $38 for each day. Will
Alex Ar [27]
Unfortunately, Katie will be $20 short

She has $40
Plus the $38 x 5 she will be earning which is $190
$190+$40 is $230

Looks like Kate needs one more day of hard work to get her bike ; )
4 0
3 years ago
Read 2 more answers
Graph y = x2 + 2. Identify the vertex of the graph. Tell whether it is a minimum or maximum
Leona [35]
Vertex is -b/2a. The variable b=2 and a=2. That finds the x coordinate of the vertex. Then to find the y coordinate you just plug the number you got for x (-1/2) into the equation. Like so:
y = 2x+2
y = 2(-1/2)+2
y = -1+2
y = 1
So your vertex is ( -1/2, 1 )
To graph your vertex you take your x coordinate (-1/2) and find it on the x axis of the graph (horizontal line). Then do the same for y (1) (on the vertical axis.
Now that you have your vertex graphed you can find out if it is minimum or maximum by looking at the direction in which the slope is going. If it goes in the positive direction (up) then it is a minimum since that is the lowest point that the line touches. If it is maximum it is opposite. The line faces down and the highest point the line touches is that point.
4 0
3 years ago
6w + 2(4w - 7) simplified​
Gemiola [76]

Answer:

14w -14

Step-by-step explanation:

6w + 2(4w - 7)

Distribute

6w+ 8w -14

Combine like terms

14w -14

8 0
3 years ago
Read 2 more answers
Need help immediately​
vekshin1
The answer is 6*square rooted*2
3 0
3 years ago
Suppose taxi fare from Logan Airport to downtown Boston is known to be normally distributed with a standard deviation of $2.50.
Mariulka [41]

Answer:

95% Confidence interval for taxi fare:  ($20.5,$24.2)

Step-by-step explanation:

We are given the following data set: for fares:

$22.10, $23.25, $21.35, $24.50, $21.90, $20.75, and $22.65

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{156.5}{7} = 22.35

95% Confidence interval:

\bar{x} \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

22.35 \pm 1.96(\frac{2.5}{\sqrt{7}} ) = 22.35 \pm 1.85 = (20.5,24.2)

6 0
3 years ago
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