If we know that 30% of the time is used after 9 minutes we can write this mathematically as:
By solving for x we can determine the total time allowed to play games and so:
The total time allowed to play games is 30 minutes. Since 9 minutes have lapsed 30-9=21 minutes left to play.
When A is reflected over y=-1, -1+(-1-(-2))=0, it lands on (-5, 0), when it is then reflected over x=3, 3+(3-(-5))=11, it lands on (11,0)
If you can't visualize it, draw a graph.
Answer:
Step-by-step explanation:
Total possibilities when we a roll a die at a time are 6
given we should have four for first time and then three
let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is
PROBABILITY=
Favourable chances=1
Total chances=6
Probability=
the prabability to get 4 in first roll is .
let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is
Favourable chances=1
total chances=6
probability=
the probability to get 3 in second roll irrespective of first one is
the probability to get 4 in first time and then 3 is
The probability to occur both events at a time is multiplication of individual probabilities
So,
probablility to get 4 in first roll=
probability to get 3 in second roll=
probability to occur both at a same time is = 
=
Look at intersecting points of line on x- and y-axis.
The points would be: (8,0) & (0,4)
formula of slope = (y2-y1) / (x2-x1)
(4-0)/(0-8) = -4/8 = -1/2.
