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3 years ago

Paolo, a popular basketball player in school was asked by his coach, how is your family

Computers and Technology

1 answer:

Llana [10]3 years ago

4 0

Answer:

Explanation:

how your family is encouraging and supporting his goals and ambitions and what they think of his basketball passion. whether they agree with what he is doing and are proud of him or think that he is wasting his time and not getting anywhere in life.

Paolo needs to think about how his parents and family react to him playing.

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Which of the following scenarios describes an IT professional using the Internet and computer system access in an unprofessional

pantera1 [17]

Answer:

All of the above

Explanation:

6 0

2 years ago

Hurry please i need this ASAP<br><br>What might be some advantages to keeping CSS and HTML separate?

marusya05 [52]

Answer:

The separation of HTML from CSS makes it easier to maintain sites, share style sheets across pages, and tailor pages to different environments. This is referred to as the separation of structure (or: content) from presentation.

Explanation:

I think this right don't add me right then add

6 0

2 years ago

Write a method swaparrayends() that swaps the first and last elements of its array parameter. ex: sortarray = {10, 20, 30, 40} b

Alexus [3.1K]

In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:

#include <stdio.h>

void swaparrayends(int arr[], int nrElements)
{
int temp = arr[0];
arr[0] = arr[nrElements - 1];
arr[nrElements - 1] = temp;
}

void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);

for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
}

getchar();
}

In higher languages like C# it becomes much simpler:

  static void Main(string[] args)
  {
int[] myArray = {1, 2, 3, 4, 5};
swaparrayends(myArray);
foreach (var el in myArray)
{
Console.Write(el + " ");
}

Console.ReadLine();
}

static void swaparrayends(int[] arr)
{
  int temp = arr[0];
arr[0] = arr.Last();
arr[arr.Length - 1] = temp;
}

3 0

3 years ago

Choices.

Svet_ta [14]

Answer:

1. B

2. D

3. C

4. A

5. B

Explanation:

1. To check the integrity of your hard disk and fix various file system errors, the Windows utility which should be implemented is Check disk (Chkdsk). This utility is always used with the command line interface (CLI) with the command "chkdsk."

2. An event or action took place and it caused damage to data, hardware, software and processing capability of the computer. From the statement given, security risks are being described. Any event or action that is capable of causing a problem to a computer system is considered to be a security risk and should be prevented through the use of an appropriate utility software.

3. Virus is a software program that can infect, damage and disrupts the whole computer system.

4. To protect the whole computer system, the software utility which is needed is an Anti-virus.

5. To avoid losing valuable data to your computer, the most important thing to do is to regularly back-up your files.

7 0

2 years ago

2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of

allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0

3 years ago