2 years ago

A student flips a coin 58 times. How many times can she expect the coin to land on heads.

Mathematics

2 answers:

VMariaS [17]2 years ago

8 0

Answer:

Roughly 29 times on heads

Step-by-step explanation:

A coinflip is a 50/50 chance

58 / 2 = 29~

Answer:

Roughly 29 times on heads

goldenfox [79]2 years ago

5 0

Well there’s two sides of a coin
so divide 58 by 2 to get 29

You might be interested in

Based only on the information given in the diagram, which congruence

otez555 [7]

Answer:

C is the answer according to me

3 0

2 years ago

Please help my teacher has been waiting for 30 full mniutes

anyanavicka [17]

Answer:

404.990 in^2

Step-by-step explanation:

I think, I cant be 100% sure but I'm pretty sure that's the answer, sorry if I'm wrong

3 0

3 years ago

Applying One-Step Inequalities

sergij07 [2.7K]

Answer:

1). n </=6

2). n > 27.25

3). n > 10.50

8 0

3 years ago

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at

Soloha48 [4]

The equation you can use to solve the problem is;

50/30 = 300/x

Next Cross Multiply

50x = 9000

x = 9000/50

x = 180

The building's shadow is 180 feet tall

7 0

3 years ago

What does OD=<br> Pls answer

Elodia [21]

Answer:

OD = 9.375"

Step-by-step explanation:

We can draw a line from O to B to create a triangle.

Then, Triangle ODB and Triangle ACB are similar, so their corresponding side's ratio are similar as well.

Triangle ACB, we can use pythagorean theorem to figure out CB:

AC^2 + CB^2 = AB^2

15^2 + CB^2 = 17^2

225 + CB^2 = 289

CB^2 = 64

CB = 8

Now relating the corresponding sides, we can figure out OD:

$\frac{OD}{DB}=\frac{AC}{CB}\\\frac{OD}{8-3}=\frac{15}{8}\\\frac{OD}{5}=\frac{15}{8}\\8OD=5*15\\OD=\frac{5*15}{8}\\OD=9.375$

8 0

3 years ago