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Mazyrski [523]
3 years ago
5

Will give branlliestSolve the following proportion plz: a. 18 = 8 72 ​

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
5 0

Answer:

1:48.44....

Step-by-step explanation:

872/18=48.44

Just plug it into a calculator

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Find the common ratio of the following geometric sequence.
Elanso [62]
The answer is (4/5). If you multiply the first (5/12) over and over, you get this sequence.
8 0
3 years ago
(18x-44 )(8x-10) (13y-38) geometry
xenn [34]

Simplifying

18x + -44 = 13y + -38

Reorder the terms:

-44 + 18x = 13y + -38

Reorder the terms:

-44 + 18x = -38 + 13y

Solving

-44 + 18x = -38 + 13y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '44' to each side of the equation.

-44 + 44 + 18x = -38 + 44 + 13y

Combine like terms: -44 + 44 = 0

0 + 18x = -38 + 44 + 13y

18x = -38 + 44 + 13y

Combine like terms: -38 + 44 = 6

18x = 6 + 13y

Divide each side by '18'.

x = 0.3333333333 + 0.7222222222y

Simplifying

x = 0.3333333333 + 0.7222222222y

3 0
3 years ago
The skateboard ramp has a width of 20 and a height of 16. What is its slope ( not to scale) ?​
slega [8]

Answer:

25.61 ?

Step-by-step explanation:

use Pythagoreans theorem

a^2+b^2=c^2

20^2+16^2=656

sqrt 656=25.61

4 0
2 years ago
Analyze the dot plots. What is the difference between the medians of the two data sets? mm
Anettt [7]

Answer:

4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Jerald jumped from a bungee tower. If the equation that models his height, in feet, is h = –16t2 + 729, where t is the time in s
Snezhnost [94]

Answer. First option: t > 6.25


Solution:

Height (in feet): h=-16t^2+729

For which interval of time is h less than 104 feet above the ground?

h < 104

Replacing h for -16t^2+729

-16t^2+729 < 104

Solving for h: Subtracting 729 both sides of the inequality:

-16t^2+729-729 < 104-729

-16t^2 < -625

Multiplying the inequality by -1:

(-1)(-16t^2 < -625)

16t^2 > 625

Dividing both sides of the inequality by 16:

16t^2/16 > 625/16

t^2 > 39.0625

Replacing t^2 by [ Absolute value (t) ]^2:

[ Absolute value (t) ]^2 > 39.0625

Square root both sides of the inequality:

sqrt { [ Absolute value (t) ]^2 } > sqrt (39.0625)

Absolute value (t) > 6.25

t < -6.25 or t > 6.25, but t can not be negative, then the solution is:

t > 6.25



5 0
3 years ago
Read 2 more answers
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