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3 years ago

11

Mary had swimming lessons every 3rd day and diving lessons every fifth day. If she had a swimming lesson and a diving lesson on

January 6th, when is the next date on which she will have both a swimming and diving lesson?

2 answers:

Rina8888 [55]3 years ago

6 0

15 days later, on the 21st.

Arte-miy333 [17]3 years ago

4 0

Mary will have Both swimming and diving lessons on January 14

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Mhanifa can you please help with this??? Look at the picture attached. Thanks!

EastWind [94]

Answer:

<u>Properties of a rhombus used to solve the following </u>

<em>Opposite angles are congruent</em>
<em>Diagonals are angle bisectors</em>
<em>Diagonals are perpendicular to each other</em>
<em>Adjacent angles are supplementary</em>

(30)

∠2 = ∠3 = ∠5 = 27°
∠1 = ∠4 = 180° - (2*27°) = 126°

(31)

∠4 = 70°
∠1 = ∠2 = ∠3 = ∠5 = 1/2(180° - 70°) = 1/2(110°) = 55°

(32)

∠1 = ∠2 = ∠5 = 90° - 26° = 64°
∠3 = 26°
∠4 = 90°

5 0

2 years ago

During the course of a 2,185 mile trip, the Archetti's used 5 full tanks of gasoline. The gas tank of their car holds 23 gallons

Pepsi [2]

Okay, let's use some math..

So multiply first..

2.99 * 5 = $14.95 that she has spent on gas..

23 / 5 = 4.6 gallons of gas left..

But this question is asking how much she had spent on gas, so your answer will be..
She has spent $14.95 on gas..

You can correct me if I'm wrong..

I hope this helps you!

6 0

3 years ago

What is 0.25 ÷ 5.46 (show ur work)

kenny6666 [7]

Answer:

0.04578

Step-by-step explanation:

Hope this helps somewhat.

4 0

1 year ago

Read 2 more answers

If angle YWZ = 17, what is angle WXY?

marusya05 [52]

We know that

step 1
if ∡YWZ=17°
then
∡XWZ=17°*2-----> 34°----> because triangle XWY and triangle YWZ are congruents

step 2
∡WXY=∡WZY-------> because triangle XWY and triangle YWZ are congruents
we know that
<span>the sum of the internal angles of a triangle is 180 degrees
</span>so
180°=∡XWZ+2*∡WXY---------> ∡WXY=[180-∡XWZ]/2
∡WXY=[180-34°]/2-------> ∡WXY=73°

the answer is
∡WXY=73°

5 0

3 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

2 years ago