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Andru [333]
3 years ago
5

On a test, mean score was 70 and the standard deviation of the scores was 15.

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

P(x\:

Step-by-step explanation:

To  find the probability that a randomly selected test taker scored below 50, we need to first of all determine the z-score of 50.

The z-score for a normal distribution is given by:

z=\frac{x-\bar x}{\sigma}.

From the question, the mean score is \bar x=70, the standard deviation is, \sigma=15, and the test score is x=50.

We substitute these values into the formula to get:

 z=\frac{50-70}{15}.

 z=\frac{-20}{15}=-1.33.

We now read the area that corresponds to a z-score of -1.33 from the standard normal distribution table.

From the table, a z-score of -1.33 corresponds to and area of 0.09176.

Therefore the probability that a randomly selected test taker scored below 50 is P(x\:

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Graph: Attached below ↓↓↓↓↓

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