Answer:
b. tags
Explanation:
When you write HTML code, you use tags to describe the structure of information on a webpage. These tags are represented by the following symbols <>. All of HTML is written using different types of tags such as <body>, <main>, <div>, <nav>, etc. Each of these serves a different purpose but are all used for structuring the specific information on a website so that the information is well organized and is not all on top of each other. This also allows for specific sections to be easily targeted and styles separately from the other sections.
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
Answer:
1.25
Explanation:
#instructions = 
Average CPI (old) = 0.2*6 + 0.8*1 = 1.2+0.8 = 2.0
Average CPI (new) = 0.2*12 + 0.8*1 = 2.4 + 0.8 = 3.2
Assuming Clock Rate = x
Speedup = Execution Time (old) / Execution time (new) = (2.0*5*
/x) / (3.2*5* /2x) = 4/3.2 = 1.25
Answer:
(1, 4)
(2, 7)
(0, 1)
(-1, -2)
Explanation:
to find <em>ordered pairs</em>, we plug in different values for x.
(remember, and "ordered pair" is (x, y)--the first number turns into the second number when put through the function)
<em>usually, it's easiest to plug in smaller numbers, so that it is less complicated to graph </em>
so, here's a few x values:
x = 1
y = 3x + 1
y = 3(1) + 1
y = 3 + 1
y = 4
so, when x = 1, y = 4
we write this as: (1, 4)
x = 2
y = 3x + 1
y = 3(2) + 1
y = 6 + 1
y = 7
so, when x = 2, y = 7
we write this as: (2, 7)
x = 0
y = 3x + 1
y = 3(0) + 1
y = 0 + 1
y = 1
so, when x = 0, y = 1
we write this as: (0, 1)
x = -1
y = 3x + 1
y = 3(-1) + 1
y = -3 + 1
y = -2
so, when x = -1, y = -2
we write this as: (-1, -2)
hope this helps!! have a lovely day :)
Answer:
Step 1: Determine the goal of the algorithm. ...
Step 2: Access historic and current data. ...
Step 3: Choose the right model(s) ...
Step 4: Fine tuning. ...
Step 5: Visualise your results. ...
Step 6: Running your algorithm continuously.
