Identify the hardware components in your own computer. If you don't have a computer, use a friend's, or one at work or in an NVC
1 answer:
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Answer:
Code is given below and output is attached as an image.
Explanation:
#include <iostream>
#include <fstream>
using namespace std;
bool isPalindrome(int n)
{
// Find reverse of n
int rev = 0;
for (int i = n; i > 0; i /= 10)
rev = rev * 10 + i % 10;
// If n and rev are same,then n is a palindrome
return (n == rev);
}
int main()
{
int min = 1; // Lower Bound
int max = 200; // Upper Bound
ofstream myfile;
myfile.open("palindrome.txt");
for (int i = min + 1; i < max; i++)
if (isPalindrome(i))
myfile << i << endl;
myfile.close();
return 0;
}
Answer:
Program.java
import java.util.Scanner;
public class Program {
public static boolean isPalindrome(String str){
int start = 0, end = str.length()-1;
while (start < end){
if(str.charAt(start) != str.charAt(end)){
return false;
}
start++;
end--;
}
return true;
}
public static int countPalindromePairs(String[] inarr){
int count = 0;
for(int i=0; i<inarr.length; i++){
for(int j=i+1; j<inarr.length; j++){
StringBuilder sb = new StringBuilder();
sb.append(inarr[i]).append(inarr[j]);
if(isPalindrome(sb.toString())){
count++;
}
}
}
return count == 0 ? -1 : count;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String line = sc.next();
String[] inarr = line.split(",");
int count = countPalindromePairs(inarr);
System.out.println("RESULT: "+count);
}
}
Explanation:
OUTPUT:
