Question

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equations can be used to model the height as a function of time, t, in hours? Assume that the time at t = 0 is 12:00 a.m

Answer 1

Answer:

The required equation is $y=0.5\cos (\frac{\pi t}{6})+9.5$.

Step-by-step explanation:

It is given that the height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. It means the minimum height is 9 feet and the maximum height is 10.

At x=0 is 12:00 a.m, it means the function is maximum at x=0. So, the general equation is defined as

$y=a\cos(\omega t)+b$

Where, a is amplitude, w is period, t is time in hours and b is midline.

Midline is the average of minimum and maximum height.

$b=\frac{9+10}{2}=9.5$

Amplitude is the distance of maximum of minimum value from midline.

$a=10-9.5=0.5$

Now, the equation can be written as

$y=0.5\cos(wt)+9.5$                      .... (1)

At t = 0 is 12:00 a.m, so t=3 is 3:00 a.m and the y=9.5 at x=3.

$9.5=0.5\cos(3w)+9.5$

$\cos(3w)=0$

$\cos(3w)=\cos(\frac{\pi}{2})$

$3w=\frac{\pi}{2}$

$w=\frac{\pi}{6}$

Substitute this value in equation (1).

$y=0.5\cos (\frac{\pi t}{6})+9.5$

Therefore the required equation is $y=0.5\cos (\frac{\pi t}{6})+9.5$.

Answer 2

Y=Acos(p)+m, A=amplitude, p=period, m=midline, in this case:

A=1/2, p=360(t/12)=30t, m=(10-9)/2+9=9.5 so

h(t)=(1/2)cos(30t)+9.5