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AURORKA [14]
2 years ago
14

Geometry given right triangle ABC with altitude BD drawn to hvpotenuse AC. If AD = 8

Mathematics
1 answer:
Over [174]2 years ago
4 0

Answer: 2

Step-by-step explanation:

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Please Explain How to Solve.
Shtirlitz [24]

Answer:

0.66653334

Step-by-step explanation:

The area of the face of the square is the side length x the side length. So 0.3333 x 0.3333 = 0.11108889. Since a square has 6 sides, multiply 0.11108889 with 6. So it equals 0.66653334.

6 0
2 years ago
Read 2 more answers
Can you assist me? Thanks.​
MrMuchimi
It’s been a while since I’ve done geometry, but I think this is right.
Because we are dealing with a rhombus: angles X and A are the same, so we use this to solve for x like any other algebraic expression.
After we have found x (24), we can also apply the knowledge that since angles X and M are complementary they will form a 180° line when added.
Substitute the expression for angle X with the solved for expression and subtract it from 180°. And bam! Angle M

5 0
3 years ago
Ifp * (x) = 3x ^ 2 - 4 and r(x) = 2x ^ 2 - 5x + 1 . find value r(x + 2)
valina [46]

Answer:

<h2>          r(x+2) = 2x² + 3x - 1</h2>

Step-by-step explanation:

r(x) = 2x ^ 2 - 5x +1\\\\ r(x+2) = 2(x+2)^ 2 - 5(x+2) +1\\\\ r(x+2) = 2(x^2+4x+4) - 5x-10+1\\\\ r(x+2) = 2x^2+8x+8 - 5x-9\\\\ r(x+2) = 2x^2+3x-1

7 0
3 years ago
WHAT'S 56.7X7????????????????
natulia [17]
396.9
.........................
4 0
3 years ago
Read 2 more answers
A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65m/s in 5 seconds what
artcher [175]

The acceleration is defined as the ratio between the change in velocity and the time elapsed to perform such a change.

These "changes" are indicated with the capital greek letter delta, \Delta, and when you write \Delta x you mean the difference between the finial and the inital values of the variable x:

\Delta x = x_{\text{fin}} - x_{\text{init}}

So, the acceleration is defined as

a = \dfrac{\Delta v}{\Delta t} = \dfrac{v_{\text{fin}} - v_{\text{init}}}{t_{\text{fin}} - t_{\text{init}}}

In this case, the initial velocity is 35, the final velocity is 65. Assuming we start the clock at the beginning of the observation, the inital time is 0 and the final time is 5. So, we have

a = \dfrac{65-35}{5-0} = \dfrac{30}{5} = 6m/s^2

3 0
3 years ago
Read 2 more answers
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