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marissa [1.9K]
2 years ago
9

You purchased concentrated cleaner that must be diluted (watered down) before use. Container A is the cleaner, which is a 20% so

lution. Container B is pure water. You are mixing together the contents of Container A and Container B to produce 40 gallons of 9% solution. How many gallons from each container are needed to create the 40 gallons of 9% cleaning solution? Write your answers as integers only.
Container A: 20% Cleaning Solution =

gallons


Container B: Pure Water =

gallons
Mathematics
1 answer:
34kurt2 years ago
4 0

Answer:

Amount of chemical solution = 18 gallon

Amount of pure water = 22 gallon

Step-by-step explanation:

Assume;

20% of solution = x

So,

Amount of pure water = 40 gallons - x

Amount of pure water = 40 - x

Computation:

20% of x = 9% of 40 gallon

0.2 x = 3.6

x = 3.6 / 0.2

x = 18 gallon

So,

Amount of chemical solution = 18 gallon

Amount of pure water = Total solution - Amount of chemical solution

Amount of pure water = 40 -18

Amount of pure water = 22 gallon

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Help please now i cant figure it out
12345 [234]

Answer:

a. \frac{-11}{24}

b. \frac{-3}{2} \\

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d.  \frac{11}{16}

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Step-by-step explanation:

a. \frac{-1}{6}\\ * 2\frac{3}{4} =

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4 0
3 years ago
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user100 [1]
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Pavel [41]

Answer:

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Step-by-step explanation:

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