Question

The diagonals of square abcd intersect at e. if ae = 3x – 4 and bd = 10x – 48, find ac.

Answer 1

Answer:

AC = 52

Step-by-step explanation:

the diagonals of a square are congruent and bisect each other, hence

AC = BD

2(3x - 4) = 10x - 48

6x - 8 = 10x - 48 ( subtract 10x from both sides )

- 4x - 8 = - 48 ( add 8 to both sides )

- 4x = - 40 ( divide both sides by - 4 )

x = 10

⇒ AC = 2(3 × 10 - 4) = 2 × 26 = 52