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3 years ago

Can someone PLEASE HELP ME WITH THIS QUESTION I REALLY NEED HELP

Mathematics

2 answers:

irina [24]3 years ago

4 0

I’m not going to tell u the answer if that’s okay for you but for area is multiply all of the numbers together. I hope u get the answer!

Sphinxa [80]3 years ago

3 0

Integer includes all negative and positive whole numbers including zeros

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The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normal

adell [148]

Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

$z=\frac{x-\mu}{\sigma}$

a) For x < 2:

$z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08$

From normal distribution table, P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%

b) For x = 2:

$z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08$

For x = 11:

$z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67$

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337

c) For x = 11:

$z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67$

From normal distribution table, P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

$z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08$

For x = 5:

$z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83$

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) = 0.2033- 0.0188 = 0.1845

e) For x = 5:

$z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83$

From normal distribution table, P(x < 5) = P(z < -0.83) = 0.2033

8 0

4 years ago

A ship goes at the rate of (3m-2) knots per hour. How far can it travel in (4m+9) hours?

Ber [7]

Answer: $12m^2+19m-18$

Step-by-step explanation:

Given

Speed of boat $v=3m-2\ \text{knots per hour}$

$\text{time t= }4m+9\ \text{hours}$

$\Rightarrow \text{Distance =speed}\times \text{time}$

$\Rightarrow \text{Distance d=}(3m-2)\cdot (4m+9)\\\Rightarrow d=12m^2+19m-18$

7 0

3 years ago

-2, 10, -50. Find the next two terms of this sequence. Give exact values (not decimal approximations)

lyudmila [28]

250 and - 1250

This is a geometric sequence with common ratio r = - 5

multiply each term by - 5 to obtain the next term

- 50 × - 5 = 250

250 × - 5 = - 1250

the sequence is - 2, 10, - 50, 250, - 1250

8 0

4 years ago

Read 2 more answers

Find the area of this trapezoid. Include the correct unit in your answer.

NemiM [27]

Answer:

$\displaystyle A _{ \text{trapezoid}} = 70 {m}^{2}$

Step-by-step explanation:

we are given a trapezoid

we want to figure out the area

remember that,

$\displaystyle A _{ \text{trapezoid}} = \frac{a + b}{2} h$

where a and b represent the parallel lines and h represents the height

we get from the pic that a and b are 5 and 15 respectively and h is 7

so substitute:

$\displaystyle A _{ \text{trapezoid}} = \frac{5 + 15}{2} \times 7$

simplify addition:

$\displaystyle A _{ \text{trapezoid}} = \frac{20}{2} \times 7$

simplify division:

$\displaystyle A _{ \text{trapezoid}} = 10\times 7$

simplify multiplication:

$\displaystyle A _{ \text{trapezoid}} = 70$

since we multiply two same units we of course have to use square unit

hence,

$\displaystyle A _{ \text{trapezoid}} = 70 {m}^{2}$

4 0

3 years ago

Which graph shows the solutions to<br> the inequality? PLSSS HELPPP

gavmur [86]

It’s the third graph down!!

7 0

3 years ago