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Lynna [10]
3 years ago
13

PLS HELP ME ASAP NOW PLS ILL GIVE EXTRA POINTS PLE HELP ME

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
7 0

Answer:

your not showing the whole thing

Step-by-step explanation:

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Find the value of the expression 0.5^10/0.5^7
SIZIF [17.4K]

Answer:

The solution is:

  • \frac{0.5^{10}}{0.5^7}=0.125

Step-by-step explanation:

Given the expression

0.5^{10}\div 0.5^7

Solving

\frac{0.5^{10}}{0.5^7}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

so

\frac{0.5^{10}}{0.5^7}=0.5^{10-7}

\mathrm{Subtract\:the\:numbers:}\:10-7=3

=0.5^3

=0.125        ∵ 0.5^3=0.125

Therefore, the solution is:

\frac{0.5^{10}}{0.5^7}=0.125

7 0
3 years ago
In a translation, the line segments that connect each point on the preimage to the corresponding point on the image are not only
makvit [3.9K]
Parallel because congruency and parallelism is somehow similar and that word fits in perfectly
5 0
3 years ago
Debra has to decide on paint colors for her house. There is a 90% chance she will chose gray for the living room. There is a 70%
lbvjy [14]
What are the answer choices
3 0
3 years ago
Read 2 more answers
If f(x) = -(1/x^3) and x takes on successive values from -10 to 0.1 ,
prohojiy [21]
Alright, this one is a little interesting... Let's perform some tests to figure out what is happening:
f(-10) = -(1/(-10)^3) = -(1/-1000) = 1/1000  (positive)
f(-5) = -(1/(-5)^3) = -(1/-125) = 1/125 (positive, bigger than the last one)
f(-1) = -(1/(-1)^3) = -(1/-1) = 1 (positive, bigger than the last one)
f(-0.1) = -(1/(-0.1)^3) = -(1/-0.001) = 1/0.001 = 1000 (positive, bigger than the last one)
f(0) = -(1/0^3) = undefined!
f(0.1) = -(1/(0.1)^3) = -(1/0.001) = -1/0.001 = -1000 (negative)
f(1) = -(1/1^3) = -(1/1) = -1 (negative, but bigger than last one)

It's a little confusing with the undefined part at x = 0. What I can say is this, it is increasing from -10 up to 0, something weird happens at 0 and it resets, and starts increasing from 0 up to 0.1. 

I guess A would be the best answer?

3 0
3 years ago
Prove that there are no solutions in integers x and y to the equation 2x^2 + 5y^2 = 14
iren [92.7K]
Solve the equation for y using the formula for slope: y + mx + b

2x^2 + 5y^2 = 14
5y^2 = -2x^2 + 14
y^2 = -2/5x^2 + 14/5
y = the sq root of -2x^2/5 + 14/5

There is no integer solution to the square root of a negative number.
5 0
3 years ago
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