4 years ago

What is the sum of the first five terms of s geometric series with a1=6 and r=1/3

Mathematics

1 answer:

omeli [17]4 years ago

7 0

$S_{5}$ = $\frac{242}{27}$ = 8 $\frac{26}{27}$

The sum of n terms in a geometric series is

$S_{n}$ = $\frac{a(1-r^n)}{1-r}$ , hence

$S_{5}$ = $\frac{6(1-(1/3)^5)}{1-1/3}$

= $\frac{6(1-1/243)}{2/3}$

= 9 ( $\frac{242}{243}$ ) = $\frac{242}{27}$

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