<em>Answer:</em>
<u>Tony</u> has 45 dollars
<u>Milan</u> has 15 dollars
<u>Lucy</u> has 25 dollars
<em>Explanation:</em>
<u>Let </u><u><em>x</em></u><u> represent the amount of money Milan has in his wallet.</u>
TONY: 3x
MILAN: x
LUCY: x+10
<u>Lucy, Milan, and Tony have a total of $85 in their wallets. Hence, the following equation.</u>
<u />
3x+x+x+10=85
5x+10=85
5x=75
x=75/5
x=15
Tony has 45 dollars (3*15=45)
Milan has 15 dollars (x=15)
Lucy has 25 dollars (10+15=25)
Let;
A(-8,6) B(6,6) C(6, -4) D(-8, -4)
Let's find the length AB
x₁= -8 y₁=6 x₂=6 y₂=6
We will use the distance formula;
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
![=\sqrt[]{(6+8)^2+(6-6)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%286%2B8%29%5E2%2B%286-6%29%5E2%7D)
![=\sqrt[]{14^2+0}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B14%5E2%2B0%7D)
Next, we will find the width BC
B(6,6) C(6, -4)
x₁= 6 y₁=6 x₂=6 y₂=-4
substitute into the distance formula;
![d=\sqrt[]{(6-6)^2+(-4-6)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%286-6%29%5E2%2B%28-4-6%29%5E2%7D)
![=\sqrt[]{(-10)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B%28-10%29%5E2%7D)
![=\sqrt[]{100}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B%5D%7B100%7D)
Area = l x w
= 14 x 10
= 140 square units
8.95 x 2 = 17.90
23.65 - 17.90 = 5.75
The answer is £5.75
Well, each centimeter is 10 millimeters. 25cm=250mm
N-O
———-
O
(New - old
—————
O)
8750-12500
——————-
12500
-3750
————
12500
=030%
