Fill in the blanks with the correct types of energy.
2 answers:
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Answer: The given reaction is non-spontaneous at low temperatures and spontaneous at high temperatures.
Explanation:
We know that relation between free energy and enthalpy is as follows.
As in the given drawing, solid is converting into gas. This means that there is occurring an increase in entropy of the system. This also means that the enthalpy change will also be positive.
Free energy change is negative (spontaneous) at high temperature and free energy change is positive at low temperature.
Hence, we can conclude that the given reaction is non-spontaneous at low temperatures and spontaneous at high temperatures.
Answer:
+2
Explanation:
If a compound existed, we would identify the oxidation state of sulfur using the following logic:
- oxygen is more electronegative than sulfur, so it's more electron-withdrawing and it should have a negative oxidation state producing a positive oxidation state for sulfur;
- oxygen typically has an oxidation state of -2;
- we may then apply the fact that SO is expected to be a molecule with a net charge of 0;
- if the net charge is 0 and the oxidation state of oxygen is -2, we may set the oxidation state of S to x;
- write the equation for the net charge of 0 by adding all individual charges of the two atoms:
;
- hence, x = 2.
That said, in this hypothetical compound S would have an oxidation state of +2.