What is the oxidation state of S in so ??
1 answer:
Answer:
+2
Explanation:
If a compound existed, we would identify the oxidation state of sulfur using the following logic:
- oxygen is more electronegative than sulfur, so it's more electron-withdrawing and it should have a negative oxidation state producing a positive oxidation state for sulfur;
- oxygen typically has an oxidation state of -2;
- we may then apply the fact that SO is expected to be a molecule with a net charge of 0;
- if the net charge is 0 and the oxidation state of oxygen is -2, we may set the oxidation state of S to x;
- write the equation for the net charge of 0 by adding all individual charges of the two atoms:
;
- hence, x = 2.
That said, in this hypothetical compound S would have an oxidation state of +2.
You might be interested in
= k
<u>Explanation:</u>
The relation between volume, V of gas and Temperature, T of a gas is related by Charles Law.
This law states that the volume of a given amount of gas held at a constant pressure is directly proportional to the Kelvin temperature
Thus,
= k
where k is a constant
Therefore,
=
=
...
This shows, as the volume of a gas goes up, the temperature also goes up and vice-versa.