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Maslowich
4 years ago
7

When the pressure changes from 1.21 atm to 2.52 atm, the volume changes from 3.75 L to 1.72 L and the temperature changes from 2

93 K to _ k
Chemistry
1 answer:
weqwewe [10]4 years ago
6 0

Answer is 280 K


<em>Explanation:</em>


Let's assume that the gas is an ideal gas.

 

Then we can use combined gas law,

<span> PV/T = k (constant)</span>

 

<span>Where, P is the pressure of the gas, V is volume of the gas and T is the temperature of the gas in Kelvin.</span>

 

For two situations, we can use 

P₁V₁/T₁= P₂V₂/T₂

 

P₁ = 1.21 atm  

V₁ = 3.75 L  

T₁ = 293 K

P₂ = 2.52 atm

V₂ = 1.72 L

T₂ = ?

 

From substitution,

  1.21 atm x 3.75 L / 293 K = 2.52 atm x 1.72 L / T₂

                                      T₂ = (2.52 atm x 1.72 L x 293 K) / (1.21 atm x 3.75 L)

                                      T₂ = 279.9 K

                                      T₂ = 280 K

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