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Maslowich
4 years ago
7

When the pressure changes from 1.21 atm to 2.52 atm, the volume changes from 3.75 L to 1.72 L and the temperature changes from 2

93 K to _ k
Chemistry
1 answer:
weqwewe [10]4 years ago
6 0

Answer is 280 K


<em>Explanation:</em>


Let's assume that the gas is an ideal gas.

 

Then we can use combined gas law,

<span> PV/T = k (constant)</span>

 

<span>Where, P is the pressure of the gas, V is volume of the gas and T is the temperature of the gas in Kelvin.</span>

 

For two situations, we can use 

P₁V₁/T₁= P₂V₂/T₂

 

P₁ = 1.21 atm  

V₁ = 3.75 L  

T₁ = 293 K

P₂ = 2.52 atm

V₂ = 1.72 L

T₂ = ?

 

From substitution,

  1.21 atm x 3.75 L / 293 K = 2.52 atm x 1.72 L / T₂

                                      T₂ = (2.52 atm x 1.72 L x 293 K) / (1.21 atm x 3.75 L)

                                      T₂ = 279.9 K

                                      T₂ = 280 K

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If 0.255 moles of AgNO₃ react with 0.155 moles of H₂SO₄ according to this UNBALANCED equation below, how many grams of Ag₂SO₄ co
Ber [7]

Answer: 6.162g of Ag2SO4 could be formed

Explanation:

Given;

0.255 moles of AgNO3

0.155 moles of H2SO4

Balanced equation will be given as;

2AgNO3(aq) + H2SO4(aq) -> Ag2SO4(s) + 2HNO3(aq)

Seeing that 2 moles of AgNO3 is required to react with 1 moles of H2SO4 to produce 1 mole of Ag2SO4,

Therefore the number of moles of Ag2SO4 produced is given by,

n(Ag2SO4) = 0.255 mol of AgNO3 ×

[0.155mol H2SO4 ÷ 2 mol AgNO3] x

[ 1 mol Ag2SO4 ÷ 1 mol H2SO4]

= 0.0198 mol of Ag2SO4.

mass = no of moles x molar mass

From literature, molar mass of Ag2SO4 = 311.799g/mol.

Thus,

Mass = 0.0198 x 311.799

= 6.162g

Therefore, 6.162g of Ag2SO4 could be formed

4 0
3 years ago
What happens during a lunar eclipse?
Alexeev081 [22]

Answer:

<h2>A.EARTH PASSES BETWEEN THE SUN AND THE MOON</h2>

Explanation:

When Earth passes directly between Sun and Moon, its shadow creates a lunar eclipse.

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6 0
3 years ago
When 125.0 g of ethylene (C2H4) burns in 60.0 grams of oxygen to give carbon dioxide and water, how many grams of CO2 are formed
gizmo_the_mogwai [7]

Answer:

             66 g of CO₂

Solution:

The Balance Chemical Reaction is as follow,

                             C₂H₂  +  5/2 O₂    →    2 CO₂  +  H₂O

Or,

                             2 C₂H₂  +  5 O₂    →    4 CO₂  +  2 H₂O    -------  (1)

Step 1: Find out the limiting reagent as;

According to Equation 1,

            56.1 g (2 mole) C₂H₂ reacts with  =  160 g (5 moles) of O₂

So,

                  125 g of C₂H₂ will react with  =  X g of O₂

Solving for X,

                      X =  (125 g × 160 g) ÷ 56.1 g

                      X =  356.5 g of O₂

It means for total combustion of Ethylene we require 356.5 g of O₂, but we are only provided with 60.0 g of O₂. Therefore, O₂ is the limiting reagent and will control the yield.

Step 2: Calculate Amount of CO₂ produced as;

According to Equation 1,

              160 g (5 mole) O₂ produces  =  176 g (4 moles) of CO₂

So,

                  60.0 g of O₂ will produce  =  X g of CO₂

Solving for X,

                      X =  (60.0 g × 176 g) ÷ 160 g

                      X =  66 g of CO₂

8 0
3 years ago
The burning of 48.7 g of zns in the presence of oxygen gives 220.0 kj of heat. what is h for the reaction as written below?
mr_godi [17]

Answer : The \Delta H_{rxn} for the reaction is, 54.89 KJ

Solution : Given,

Mass of ZnS = 48.7 g

Molar mass of ZnS = 97.474 g/mole

\Delta H=220KJ

First we have to calculate the moles of ZnS.

\text{ Moles of ZnS}=\frac{\text{ Mass of ZnS}}{\text{ Molar mass of ZnS}}=\frac{48.7g}{97.474g/mole}=0.499moles

The balanced combustion reaction is,

2ZnS+3O_2\rightarrow 2ZnO+2SO_2

From the given reaction, we conclude that

As, 2 moles of ZnS gives energy = 220 KJ

So, 0.499 moles of ZnS gives energy = \frac{220KJ}{2moles}\times 0.499moles=54.89KJ

Therefore, the \Delta H_{rxn} for the reaction is, 54.89 KJ

4 0
3 years ago
Read 2 more answers
499 mg sample of CuSO4. xH2O is heated and reweighed to give a mass of 319 mg. Given that the sample contains 2 mmol of Cu; what
nevsk [136]

The value of x in CuSO4. xH2O is 5.

Given that;

Number of moles of anhydrous salt = Number of moles of hydrated salt

Number of moles of anhydrous salt = 319 × 10^-3

Mass of hydrated salt = 499 ×10^-3 g

Number of moles of anhydrous salt = 319 10^-3g/160 g/mol = 0.00199 moles

Number of moles of hydrated salt = 499 × 10^-3 g/ 160 + 18x

0.00199 =  499 × 10^-3 g/ 160 + 18x

0.00199 (160 + 18x) = 499 ×10^-3

0.318 + 0.036x = 0.499

0.036x = 0.499 - 0.318

0.036x = 0.181

x = 0.181/0.036

x = 5

Hence,  x in CuSO4. xH2O is 5.

Learn more: brainly.com/question/9743981

8 0
3 years ago
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