All categories

3 years ago

What is this?!?!!? it makes no senss

Mathematics

1 answer:

12345 [234]3 years ago

5 0

Answer:

if a varible is by itself with no key it would mean a 1 but this would most likely mean multiplication although there is no parenthesies my awnser would be 6!

Step-by-step explanation:

but that would be the same as the question.

You might be interested in

Choose the TWO factored binominals for the expression: x2+6x – 27 Question 6 options: A) (x - 3) B) (x - 9) C) (x + 6) D) (x + 9

Vera_Pavlovna [14]

Answer:

A) x-3 and D) x+9

Step-by-step explanation:

x^2 + 6x - 27

You need to find two numbers that multiply to -27 and add up to 6

Those two numbers are -3 and 9, because 9 * -3 = -27 and 9+ -3 = 6

So you add those to x and those are your two factored binomials

(x-3) and (x+9)

4 0

3 years ago

I am a 3-digit number. If rounded off to the nearest hundreds. I become 500. If rounded off to the nearest tens, I become 540. I

dimulka [17.4K]

Answer:

535 is the cirrext answer

6 0

3 years ago

Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

Which is an absurd. Therefore, $H$ doesn't contain the origin (and $H$ is a line in $IR^{2}$ ). Finally, it can't be a vector space of $V=IR^{2}$

8 0

3 years ago

Solve 4(a-3) = 22 <br> solve 5(x -6) = 65<br><br> with explanation, please <br> giving 20 points

DaniilM [7]

Step-by-step explanation:

4(a-3)=22

a-3=4-22

a-3=18

a=18+3

a=21

5(x-6)=65

x-6=65-5

x-6=60

×=60+6

x=66

hope it will help u...............

5 0

3 years ago

Read 2 more answers

Find two consecutive odd integers whose product is 1443

liberstina [14]

Let's x represents the first odd integer

The next consecutive integer would be represented as x+2.

So x and x+2 being multiplied together will give us 1443:

(x)(x+2)=1443

x^2+2x=1443

x^2+2x-1443=0

By solving the quadratic equation using the quadratic formula, x will equal to 37 and -39.

Since the problem says "integers", so I'm assuming two pairs of consecutive integers would be ok.

With that said you 1st pair will be: 37,39

Your second pair will be: -37,-39.

6 0

3 years ago