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vaieri [72.5K]
3 years ago
6

HELP PLEASE HELP , .

Mathematics
1 answer:
Otrada [13]3 years ago
3 0

Answer:

You need to plot the points at (1.5, 0) and (0,-3)

Step-by-step explanation:

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baseball card come in packs of a dozen 12 cards matt has 132 baseballcards.how many packs of baseball cards did he buy i need he
Hunter-Best [27]
Well let's see first we have to divide
132 divided by 12 is 11
Now to check and prove your answer we should use the multiplication.
11 times 12 is 132.
So now you have a solid answer with proof behind it.
If u need a sentence you might want it to go something like this;
Matt brought 11 packs of baseball cards since 132 divided by 12 is 11. 12 times 11 is 132 cards.
Hope I helped!
5 0
3 years ago
Read 2 more answers
A car is traveling at a speed of 75 km/h. Compute the speed of the car in m/s.
solniwko [45]
It would be C-20.8m/s
3 0
4 years ago
HELP PLS!!!!! One link in a chain was made from a cylinder that has a radius of 3 cm and a height of 25 cm. How much plastic coa
garri49 [273]

Answer:

471 cm^2

Step-by-step explanation:

to find the literal surface area use formula= A^L=2πrh

2(3.14)(3)(25)=

471cm^2

7 0
3 years ago
The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


4 0
4 years ago
WILL GIVE BRAINLIEST IF YOU GIVE ME A PRACTICAL ANSWER AND ITS RIGHT
Solnce55 [7]

Answer:

i dont know

Step-by-step explanation:

it will be 2 hours

7 0
3 years ago
Read 2 more answers
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