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andrew11 [14]
2 years ago
11

Please help me with this question thanks. PLEASE I REALLY NEED HELP ON THIS PROBLEM

Mathematics
1 answer:
arlik [135]2 years ago
3 0

Step One

Find the area of the base

A = s * s

s = 755.5 feet

Area = 755.5^2

Area = 570780.25 square feet.


Step two

Multiply the volume by 3

V = 1/3 B * h

3*V = B * h

V = 85600000

85600000 * 3 = B * h

256800000 = B * h


Step Three

Divide by B

B = 570780.25


256800000 = 570780.25 * h

256800000 / 570780.25 = h

449.91 feet = h

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Goryan [66]
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3 0
3 years ago
How do I get the recursive and explicit formulas of this: ..., -3, -18, -108, ...​
PtichkaEL [24]

Answer: multiply by 6

Step-by-step explanation:

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8 0
3 years ago
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

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The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
What is the product 3x5(2x2+4x+1)
lesya692 [45]

Answer:

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Step-by-step explanation:

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3x^5(2x^2+4x+1)

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a^m\imes a^n=a^{m+n}

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3 0
3 years ago
Find three consecutive integers whose sum is 57????
Setler79 [48]

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Check your answer:  18+19+20=57                 57=57  Check

7 0
3 years ago
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