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3 years ago

Please help me with this question thanks. PLEASE I REALLY NEED HELP ON THIS PROBLEM

Mathematics

1 answer:

arlik [135]3 years ago

3 0

Step One

Find the area of the base

A = s * s

s = 755.5 feet

Area = 755.5^2

Area = 570780.25 square feet.

Step two

Multiply the volume by 3

V = 1/3 B * h

3*V = B * h

V = 85600000

85600000 * 3 = B * h

256800000 = B * h

Step Three

Divide by B

B = 570780.25

256800000 = 570780.25 * h

256800000 / 570780.25 = h

449.91 feet = h

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3 years ago

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3 years ago

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What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.

Paul [167]

Answer:

1.60 $ft^{2}$

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

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So that,

for the inner part of the pipe,

r = $\frac{diameter}{2}$

= $\frac{5}{2}$

= 2.5 feet

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= 3.14 x $(2.5)^{2}$

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r = $\frac{5.2}{2}$

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3 years ago

The line a bus arrives at the bus stop every 25 minutes, and the line b bus arrives every 15 minutes.Both are at the stop right

vova2212 [387]

Answer:

after 75 minutes

Step-by-step explanation:

The least common multiple (LCM) of 15 and 25 is 75. It can be found a couple of ways:

1. List the factors of each number and find the product of the unique ones:

15 = 3·5

25 = 5²

The LCM is 3·5² = 75.

2. Find the greatest common divisor (GCD) and divide the product of the numbers by that value. From the above list of factors, we see that 5 is the GCD of 15 and 25. Then the LCM is ...

15·25/5 = 75

Or, you can simply list multiples of each number and see what the smallest number is that is in both lists:

15, 30, 45, 60, <em>75</em>, 90

25, 50, <em>75</em>, 100

The two buses will appear together again after 75 minutes.

5 0

3 years ago