.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 ) ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
-2a =38
a = -19
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0 .... b = 15
the center is :w(-19,15)
The answer is 2,-8.
But I am not sure. Hope this will help you!
(r + 10)(r - 4)
To double check:
r * r is r^2
10 * r = 10r; -4 * r = -4r
Combine to get 6r.
-4 * 10 = -40
Answer:
186.4056
Step-by-step explanation:
Used a calculator, this is correct
Answer:
x=30, and angle A equals 132°.
Step-by-step explanation:
Since the angles are alternate-interior, both angles A and B equal the same amount. To figure out the value of <em>x</em>, you'd need to set up your equation like this:
5x-18°=3x+42°
You would need to solve for <em>x</em>, which should equal to 30.
Once you get your <em>x</em>, you need to plug it in into the equation of angle A, which is 5x-18°:
5(30)-18°
150-18°
Angle A = 132°.
