A trampoline is on sale for 50% off. What was the original price if the sale price is $31?

Mathematics

2 answers:

Sergio039 [100]3 years ago

8 0

Answer:

$62

Step-by-step explanation:

Hello it's $62 because 31 x 2 = 62 and it was half off so that is why its $62

Snowcat [4.5K]3 years ago

8 0

Answer:

The original price is 62 dollars.

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Asafa runs 0.75 kilometers in 6 minutes. Jemaine runs 3,000 meters in half an hour. Who ran at a faster rate?

Lorico [155]

Answer:

Asafa ran at a faster rate

Step-by-step explanation:

<u>Asafa's speed:</u>

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A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig

Vaselesa [24]

Answer:

a) Depth changing rate of change is $0.24m/min$ , When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of $0.17m/min$ , When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them $\frac{3.5}{10} =\frac{a}{h}$ , then $a=0.35h$ .

a) As we have that volume is $V=\frac{1}{2} 2ahL=ahL$ , then $V=(0.35h^{2})L$ , so we can derivate it $\frac{dV}{dt}=2(0.35h)L\frac{dh}{dt}$ due to the chain rule, then we clean this expression for $\frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt}$ and compute with the knowns $\frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min$ , is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is $2a=0.7h$ , we can derivate it and obtain $\frac{da}{dt}=0.7\frac{dh}{dt} =0.7*0.24m/min=0.17m/min$ The width of the top of the water is changing, When the water is 6 meters deep at this rate