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3 years ago

13

How many gallons of a 50% antifreeze solution must be mixed with 70 gallons of 30% antifreeze to get a mixture that is 40% antif

reeze?

1 answer:

Colt1911 [192]3 years ago

5 0

Answer:

70 gallons

Step-by-step explanation:

x gallon of 50%

x * 0.5 + 70 * 0.3 = (x + 70) * 0.4

0.5x + 21 = 0.4x + 28

0.1x = 7

x = 70

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How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% a

Blababa [14]

To Find :

How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.

Solution :

Let, x gallons of 80% antifreeze solution is required :

So,

$(x \times 80) + ( 100 \times 20 ) = (x + 100 )\times 70\\\\8x + 200 = 7( x + 100)\\\\x = 500$

Therefore, 500 gallons of 80% antifreeze solution is required.

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