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Ivan
2 years ago
13

Is y=-3x+2 a function? why is it/is it not a function?

Mathematics
1 answer:
solong [7]2 years ago
3 0

It is a function.

You can try plot the graph of that equation and then plot a vertical line. You will see that the graph will only intercept the vertical line only once. That is a function.

Or you can look at the equation. Functions have the equations that start with "y=". Rather say that if you see "y" only (not y² or y³ just only y) then that is mostly a function.

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Select the correct answer from each drop-down menu.
sdas [7]

Answer:

see below

Step-by-step explanation:

12 banana muffins, 10 chocolate muffins, 6 blueberry muffins, and 7 vanilla muffins.

The total number of muffins is 35 muffins

P(vanilla) = number of vanilla/ total

               = 7/35

               = 1/5

This is not likely to occur so it is an unlikely event

3 0
3 years ago
Read 2 more answers
NEED HELP ASAP <br> WILL GIVE BRAIN
34kurt
Im really dumb i srry!
7 0
2 years ago
Which statement is true? 5 6 8 27 을 ll &lt; - 3 8 4 8 6 6
Neko [114]
Fractions

We are going to be checking each statement in order to find which of them are correct:

<h2>5/6 < 6/8 - 5/6 is smaller than 6/8</h2>

We can see that in the drawing 3/8 is smaller than 5/6. Then this statement is false.

<h2>4/6 < 5/8 - 4/6 is smaller than 5/8</h2>

We can see that in the drawing 5/8 is smaller than 4/6. Then this statement is false.

<h2>2/6 = 3/8 - 2/6 is equal to 3/8</h2>

We can see that in the drawing 3/8 is bigger than 2/6. Then this statement is false.

<h2>3/6 = 4/8 - 3/6 is equal to 4/8</h2>

We can see that in the drawing 4/8 is equal to 3/6. Then this statement is true.

<h2>Answer: 3/6 = 4/8</h2>

6 0
1 year ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
Evaluate <br> f(x)=5x-3<br> f(5) =
Kaylis [27]

f(x)=5x-3

use the substitution method

f(5)=(5)(5)-3

multiply the parentheses first

using: PEDMAS

P=Parentheses

E= Exponents

D=Division

M=Multiplication

A= Addition

S=Subtraction

(5)(5)=25

25-3

=22

answer:

f(5)=22

5 0
3 years ago
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