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Lerok [7]
3 years ago
6

What do i do?? i just have to find what the the question marks show.

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0
------------------------------------------------------
Given information
------------------------------------------------------
100%  = $27.60

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Rewriting it
------------------------------------------------------
\$27.60 = 100 \%
\$1 = 100 \div 27.60 \%
\$1 =  \frac{250}{69} \%

------------------------------------------------------
Find $4.14 in percentage
------------------------------------------------------
\$1 = \frac{250}{69} \%
\$4.14 =  \frac{250}{69}  \times 4.14
\$4.14 = 15%

------------------------------------------------------
Answer: 15%
------------------------------------------------------


------------------------------------------------------
Find $31.74 in percentage
------------------------------------------------------
\$1 = \frac{250}{69} \%
\$31.74 = \frac{250}{69} \times 31.74
$31.74 = 115%

------------------------------------------------------
Answer: 115%
------------------------------------------------------
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Answer:

Part 1) A=60\ ft^2

Part 2) A=80\ cm^2

Part 3) A=96\ m^2

Part 4) A=144\ cm^2

Part 5) A=9\ m^2

Part 6) A=(49\pi -33)\ in^2

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

A=bh

where

b is the base of rectangle

h is the height of rectangle

so

A=(12)(7)-(8)(3)

A=84-24

A=60\ ft^2

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

A=b^2

where

b is the length side of the square

so

A=(12)(8)-(4^2)

A=96-16

A=80\ cm^2

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

A=4(4)(5)+(4^2)

A=80+16

A=96\ m^2

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

A=(15^2)-(9^2)

A=225-81

A=144\ cm^2

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

A=\frac{1}{2}(b)(h)

where

b is the base of triangle

h is the height of triangle

so

A=\frac{1}{2}(6)(7)-(6)(2)

A=21-12

A=9\ m^2

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

so

A=\pi (7^2)-(3)(11)

A=(49\pi -33)\ in^2

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