What is the answer to this problem

PLS HELP I WILL MARK BRAINLIEST

lorasvet [3.4K]

Answer:

$31.44

Step-by-step explanation:

29.95 * .05 = 1.49

29.95 + 1.49= 31.44 (you add because its tax)

hope this helps! :)

5 0

3 years ago

Read 2 more answers

Jimmy Walked a total of 6 miles last week. This week, he walks 2 miles each hour. If he walks 6 hours this week, how many miles

arlik [135]

Answer:

18 miles

Step-by-step explanation:

Find how many miles he walked this week by multiplying 2 by 6:

2(6)

= 12

Add this to 6, since he walked 6 miles last week:

12 + 6

= 18

So, in all, he will have walked 18 miles

4 0

3 years ago

Solving equations using Zero-Product property

FrozenT [24]

Answer:if y=0

Step-by-step explanation: view y as 0, so you have 2*0*(-8+0+7)=0

every number multiplied by 0 is 0 so 2*0 is 0 then in the brackets you will have -1. So the final line is 0*-1=0 like I said every number multiplied for 0 is 0 the equation is true for y=0

7 0

3 years ago

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George has a pair of unusually labelled dice. One die is labeled with the numbers 1, 2, 2,3, 3, and 4. The other die is labelled

DIA [1.3K]

Answer:

1 out of 12

Step-by-step explanation:

3 0

3 years ago

How do i solve that question?

yawa3891 [41]

a) The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

b) The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ .

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ .

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

$6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C$

Where $C$ is the integration constant.

By table of integrals we find the solution for each integral:

$-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C$

If we know that $x = 0$ and $y = 1$ , then the integration constant is $C = -2$ .

The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$

b) In this case we need to solve a first order ordinary differential equation of the following form:

$\frac{dy}{dx} + p(x) \cdot y = q(x)$ (2)

Where:

$p(x)$ - Integrating factor
$q(x)$ - Particular function

Hence, the ordinary differential equation is equivalent to this form:

$\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x}$ (3)

The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ . $\blacksquare$

The solution for (2) is presented below:

$y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C$ (4)

Where $C$ is the integration constant.

If we know that $p(x) = -\frac{1}{x}$ and $q(x) = x^{2} + \frac{1}{x}$ , then the solution of the ordinary differential equation is:

$y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C$

$y = x\int {x} \, dx + x\int\, dx + C$

$y = \frac{x^{3}}{2}+x^{2}+C$

If we know that $x = 1$ and $y = -1$ , then the particular solution is:

$y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ . $\blacksquare$

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

3 0

2 years ago