Line BE and KE are the same length, so set the 2 equations to equal and solve for P.
7p+7 = 37-3p
Add 3 p to both sides:
10p +7 = 37
Subtract 7 from each side:
10p = 30
Divide both sides by 10:
p = 30/10
p = 3
The answer is B.
Form the ratio 560/2800 and then mult. the result by 100%:
560
--------- * 100% = 20%
2800
Answer: standard deviation = 8
This is because mu = 75 is the mean, which is at the very exact center of this distribution. One space to the right is 83, which is 83-75 = 8 units away from the center. This distance is exactly one standard deviation. We can say "83 is one standard deviation larger than 75".
Or you could note the distance from 67 to 75 is also 8, because 75-67 = 8. Each tickmark represents stepping one standard deviation in distance.
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Last one 1/4x
because the opposite of 1/4 is 4/1