Answer:
AC = (20+ 10q)
Step-by-step explanation:
Given that,
Total cost, TC = 20q + 10q²
We need to find AC i.e. average cost.
It can be solved as follows :
So, the value of AC is (20+ 10q).
Answer:
c) 12/15 = 4/5
Step-by-step explanation:
imagine we mirror the triangle up, so that Z is on top.
then you can clearly see that 6 is cos(X) times r (and r is then 7.5).
XY is sin(X)×7.5
and again, 7.5 is r (the line making the X angle).
so, the cosine ratio of X is
6 = cos(X)×7.5
cos(X) = 6/7.5 or then 12/15. or simplified 4/5.
Answer:
G(3, 1), H(2, 3)
Step-by-step explanation:
When D is the midpoint of EG, it means ...
D = (E + G)/2
or
G = 2D -E = 2(3,4) -(3,7) = (2·3-3, 2·4-7) = (3, 1)
Likewise, H is ...
H = 2D -F = 2(3,4) -(4,5) = (2·3-4, 2·4-5) = (2, 3)
Answer:
12 feet
Step-by-step explanation:
As a ladder is leaning against a house, it forms right angle triangle. And for right angleΔ, we use Pythagoras theorem.i.e
P²+B²= H²
Where,
'P' is perpendicular i.e the distance from the top of the ladder to the ground
'B' is base i.e be the distance from the bottom of the ladder to the house
'H' is hypotenuse i.e 13
considering 'x' as perpendicular
So, base would be 'x-7'
Applying Pythagoras theorem,
x² + (x-7)²= 13²
x² +x² -14x +49 =169
2x² -14x -120= 0
x² -7x -60=0 ----> solving the quadratic equation
x² + 5x -12x-60=0
x(x+5) -12(x+5)=0
Either : x+5=0 => x=-5
OR: x-12=0 => x=12
We'll choose the positive length.
therefore , The distance from the bottom of the ladder to the house is 12 feet
Answer:
sorry to answer late but..
Step-by-step explanation:
= 
the wings of the real plane are 12 meters or 1200 cm
we want to solve for the scale, sooo do the algebra...get scale by it self..
real * 
= scale
1200 * = 16
The scale model wings are 16 cm 2.54 cm is one inch so the wings are approx. 6.3 inches
