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andrew-mc [135]
3 years ago
14

The greens are Gavin g a well built in their backyard on Monday 110 feet of the well was dug and another 72 feet was dug on Tues

day how many feet below ground was the well dug. Expressed as an integer
Mathematics
1 answer:
Simora [160]3 years ago
6 0

Answer:

182 feets

Step-by-step explanation:

Given :

Feets dug on Monday 110 feets

Feets dug on Tuesday = 72 feets

Total number fo feets below the ground :

Feets dug on Monday + Feets dug on Tuesday

110 feets + 72 feets = 182 feets

Total feets below the ground is 182 feets

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Find the product (a^2-b)(5a^2+6b)
Pie

Answer:

5a^​4​​+a^​2​​b−6b​^2​​

Step-by-step explanation:

1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.

5a^4+6a^2b−5ba^2−6b^2

2. Collect like terms.

5a^4+(6a^2b−5a^2b)−6b^2

3. Simplify.

5a^4+a^2b−6b^2

7 0
3 years ago
A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T
Oksanka [162]

Answer:

The null and alternative hypotheses are:

H_{0}:\mu=75

H_{a} : \mu>75

Under the null hypothesis, the test statistic is:

t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }

Where:

\bar{x} =83 is the sample mean

s=9.8206 is the sample standard deviation

n=10 is the sample size

\therefore t= \frac{83-75}{\frac{9.8206}{\sqrt{10}} }

         =2.58

Now, we can find the right tailed t critical value at 0.01 significance level for df = n-1 = 10 - 1 = 9 using the t distribution table. The t critical value is given below:

t_{critical} =2.821

Since the test statistic is less than the t critical value, we therefore, fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the people do better with the new edition.

7 0
3 years ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
On April 1, 1986, Casey deposited $1150 into a savings account paying 9.6% interest, compounded quarterly. If he hasn't made any
dalvyx [7]
According to the 72 rule
72/rate=time
72÷9.6=7.5 years

Another way to solve by using the main equation
2300=1150(1+0.096/4)^4t
Solve for t
t=((log(2,300÷1,150)÷log(1+(0.096÷4))÷4))=7.31years

Hope it helps :-)
7 0
3 years ago
Read 2 more answers
If the base is 8 in. and the height is 7 in. What is the area?
kap26 [50]

Answer:

The formula of area is Pi×R×R

and then you add all sides and answer of your question is 30cm

8 0
3 years ago
Read 2 more answers
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