Answer:
5a^4+a^2b−6b^2
Step-by-step explanation:
1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.
5a^4+6a^2b−5ba^2−6b^2
2. Collect like terms.
5a^4+(6a^2b−5a^2b)−6b^2
3. Simplify.
5a^4+a^2b−6b^2
Answer:
The null and alternative hypotheses are:


Under the null hypothesis, the test statistic is:

Where:
is the sample mean
is the sample standard deviation
is the sample size


Now, we can find the right tailed t critical value at 0.01 significance level for df = n-1 = 10 - 1 = 9 using the t distribution table. The t critical value is given below:
Since the test statistic is less than the t critical value, we therefore, fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the people do better with the new edition.
We can rewrite the expression under the radical as

then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that

since both
and
return the same number
, and
captures both possibilities. From here, we have

The absolute values disappear on all but the
term because all of
,
and
are positive, while
could potentially be negative. So we end up with

According to the 72 rule
72/rate=time
72÷9.6=7.5 years
Another way to solve by using the main equation
2300=1150(1+0.096/4)^4t
Solve for t
t=((log(2,300÷1,150)÷log(1+(0.096÷4))÷4))=7.31years
Hope it helps :-)
Answer:
The formula of area is Pi×R×R
and then you add all sides and answer of your question is 30cm