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Montano1993 [528]
3 years ago
11

How much of the circle is shaded? 1/4 and 2/5

Mathematics
1 answer:
IgorLugansk [536]3 years ago
4 0

Answer:

is there supposed to be a photo connected ??

Step-by-step explanation:

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Rewrite as a logarithmic equation. e^9=y
kolbaska11 [484]
Log y=9.
e


Drop first and make it logs base.
Y sits beside it
And 9 becomes answer
Therefore e = certain #
And to the power (which is Y) will give you answer of 9

4 0
3 years ago
June runs a little slower than carlos. She ran 1/4 of a mile in 3minutes. How long will it take her to run a full miles
Arlecino [84]
It will take her 12 minutes to run a full mile
6 0
3 years ago
identify the graph of 9x^2-25y^2=225 for t(0 5) and write an equation of the translated or rotated graph in general form
tamaranim1 [39]

ANSWER

The required equation is:

9 {x}^{2}  - 25{y}^{2}  + 250y  - 85 0=0

EXPLANATION

The given equation is

9 {x}^{2}  - 25 {y}^{2}  = 225

Dividing through by 225 we obtain;

\frac{ {x}^{2} }{25}  -  \frac{ {y}^{2} }{9}  = 1

This is a hyperbola that has it's centre at the origin.

If this hyperbola is translated so that its center is now at (0,5).

Then its equation becomes:

\frac{ {(x - 0)}^{2} }{25}  -  \frac{ {(y - 5)}^{2} }{9}  = 1

We multiply through by 225 to get;

9 {x}^{2}  - 25( {y - 5})^{2}  = 225

We now expand to get;

9 {x}^{2}  - 25( {y}^{2} - 10y + 25 )= 225

9 {x}^{2}  - 25{y}^{2}  + 250y  - 6 25 = 225

The equation of the hyperbola in general form is

9 {x}^{2}  - 25{y}^{2}  + 250y  - 85 0=0

5 0
3 years ago
Read 2 more answers
Missing angles in triangle help
Dmitry [639]

Answer:

which one?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help me with question number 2
Mice21 [21]

Answer:

2. The area of the side walk is approximately 217 m²

3. The distance away from the sprinkler the water can spread is approximately 11 feet

4. The area of the rug is 49.6

Step-by-step explanation:

2. The dimensions of the flower bed and the sidewalks are;

The diameter of the flower bed = 20 meters

The width of the circular side walk, x = 3 meters

Therefore, the diameter of the outer edge of the side walk, D, is given as follows

D = d + 2·x (The width of the side walk is applied to both side of the circular diameter)

∴ D  = 20 + 2×3 = 26

The area of the side walk = The area of the sidewalk and the side walk = The area of the flower bed

∴ The area of the side walk, A = π·D²/4 - π·d²/4

∴ A = 3.14 × 26²/4 - 3.14 × 20²/4 = 216.66

By rounding to the nearest whole number, the area of the side walk, A ≈ 217 m²

3. Given that the area formed by the circular pattern, A = 379.94 ft.², we have;

Area of a circle = π·r²

∴ Where 'r' represents how far it can spread, we have;

π·r² = 379.94

r = √(379.94 ft.²/π) ≈ 10.997211 ft.

Therefore, the distance away from the sprinkler the water can spread, r ≈ 11 feet

4. The circumference of the rug = 24.8 meters

The circumference of a circle, C = 2·π·r

Where;

r = The radius of the circle

π = 3.1

∴ For the rug of radius 'r', C = 2·π·r = 24.8

r = 24.8/(2·π) = 12.4/π = 12.4/3.1 = 4

The area = π·r²

∴ The area of the rug = 3.1 × 4² = 49.6.

8 0
2 years ago
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