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Elza [17]
3 years ago
14

If the area of triangle ABC= 25 square feet, then the area of the rectangle ABCD is:

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0
Should be 50 square feet. Area of triangle is base x height / 2 and area of rectangle is side1 x side2. In this case, base x height = 25 x 2 = 50, and base =side1 and height=side2.
UkoKoshka [18]3 years ago
5 0
A rectangle has 2 triangle
∴ 25 feet² × 2 = 50 feet²
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10. Giselle invests $16,250 in an account that earns 4.25% interest, compounded continuously.
denis-greek [22]

Answer: <u>24 years</u>

Step-by-step explanation:

% • total = Answer

4.25% • $40,000 = Answer

.0425 • $40,000 = Answer

Answer = $1,700 per year

40,000 ÷ 1,700 = 23.5

<u>23.5 rounded to the nearest year is 24</u>

3 0
3 years ago
Could someone help me with number 19
azamat

Solving #19

<u>Take y-values from the graph</u>

  • a) (g·f)(-1) = g(f(-1)) = g(1) = 4
  • b) (g·f)(6) = g(f(6)) = g(2) = 2
  • c) (f·g)(6) = f(g(6)) = f(5) = 1
  • d) (f·g)(4) = f(g(4)) = f(2) = -2
8 0
3 years ago
If 1+4=5 2+5=12 3+6=21 8+11=
mariarad [96]
The answer is 19 because 11+8 equals 19. Lol, hope I helped. :)
8 0
3 years ago
Read 2 more answers
NEED QUICKLY <br> Write the equation of the line shown below?
grandymaker [24]

y = x + 2

Step-by-step explanation:

General formula for any straight line:

y = mx + c

Where

m = gradient

c = constant

m = y2 - y1/x2 - x1

m = (4 - ( -2))/(2 - ( -4))

m = 6/6

m = 1

y = (1)x + c

y = x + c

Substitute any coordinate from the line of the equation.

4 = 2 + c

c = 2

substitute m and c into general formula

y = mx + c

y = x + 2

8 0
3 years ago
Read 2 more answers
7. The probability that a randomly chosen student will be left-handed is .09: a) In a class of 108, find the probability that th
vampirchik [111]

Solution :

Let x be student will be left handed

P = 0.09

Using the normal approximation to binomial distribution,

a). n = 108,

    μ = np = 9.72

    $\sigma = \sqrt{np(1-p)}$

       $=\sqrt{8.8452}$

       = 2.9741

Required probability,

P(x=8) = P(7.5 < x < 8.5)

$=P\left(\frac{7.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{8.5-9.72}{2.9741}\right)$

$=P(-0.75 < z < -0.41)$

Using z table,

= P(z<-0.41)-P(z<-0.75)

= 0.3409-0.2266

= 0.1143

b). P(x=12) = P(11.5 < x < 12.5)

$=P\left(\frac{11.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{12.5-9.72}{2.9741}\right)$

$=P(0.60 < z < 0.94)$

Using z table,

= P(z< 0.94)-P(z< 0.60)

= 0.8294 - 0.7257

= 0.1006

7 0
3 years ago
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