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3 years ago

I'm not sure ic I just leave like since I can't combine

Mathematics

1 answer:

sveticcg [70]3 years ago

5 0

2 $\sqrt{12}$ - 7 $\sqrt{3}$
= 4 $\sqrt{3}$ - 7 $\sqrt{3}$
= Since, we have same bases, we can subtract!
= To get,
= -3 $\sqrt{3}$ Answer

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4 years ago

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3 years ago

Explain why the simultaneous equations y = -2/3x + 4/3 and 12x + 18y = 24 have an infinite number of solutions. What can you ded

denpristay [2]

Answer:

It's the same equation

Step-by-step explanation:

12x+18y=24

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3 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

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3 years ago